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Naya [18.7K]
3 years ago
12

Given AC with A(3, 4) and C(-9, -2), if B

Mathematics
1 answer:
babymother [125]3 years ago
6 0

Answer:

B = (- 4, \frac{1}{2} )

Step-by-step explanation:

Using the Section formula

x_{B} = \frac{7(-9)+5(3)}{7+5} = \frac{-63+15}{12} = \frac{-48}{12} = - 4

y_{B} = \frac{7(-2)+5(4)}{7+5} = \frac{-14+20}{12} = \frac{6}{12} = \frac{1}{2}

Thus coordinates of B = (- 4, \frac{1}{2} )

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Why is looking at cash flow an important step in a good financial plan?
4vir4ik [10]

Answer:

Cash flow refers to the constant movement of money, both where and how much you're spending as well as how much you're earning in return.

Step-by-step explanation:

5 0
3 years ago
I will give brainiest to whoever answers correctly !!
pogonyaev
I don’t know if this is the right answer

700*.075 ÷ 24 will give you your monthly payment.

Explanation: brainly.com/question/9271155
8 0
3 years ago
Write the first five terms of the sequence described by the recursive formula f(1)=2,f(x)=f(x-1)*4
VladimirAG [237]

Answer:

2,8,32,128,512

Step-by-step explanation:

f(x)=f(x-1)*4

f(1)=2

f(2)=f(2-1)*4=f(1)*4=2*4=8

f(3)=f(3-1)*4=f(2)*4=8*4=32

f(4)=f(4-1)*4=f(3)*4=32*4=128

f(5)=f(5-1)*4=f(4)*4=128*4=512

5 0
3 years ago
The Sweet Shoppe wishes to sell a special mix for Valentine’s Day that consists of Dark Chocolate that costs $4.00 per lb and Mi
Mashutka [201]

Answer: Quantity of Dark Chocolate used = 15 lb

 Quantity of Milk Chocolate used  = 35 lb

Step-by-step explanation:

Let x = Quantity of Dark Chocolate.

y =  Quantity of Milk Chocolate.

As per given , we have the following system of equations:

x+y= 50-------------(1)\\\\ 4x+2y=50\times2.60\\\\ 4x+2y=130-----------(2)

Multiply equation (1) by 2 , we get

2x+2y= 100-------(3)

Eliminate equation (3) from equation (2) , we get

2x=30\\\Rightarrow\ x=15

Put x= 15 in (1) , we get 15+y=50

⇒ y=35

Therefore , Quantity of Dark Chocolate used = 15 lb

 Quantity of Milk Chocolate used  = 35 lb

8 0
4 years ago
Help me please and pls explain how you got your answer.
enyata [817]

l \parallel m\Rightarrow  m\angle2 =m\angle6 = 102°\\ m\angle1 + m\angle2 = 180°\Leftrightarrow m\angle1 = 180° - m\angle2 = 180° - 102° = 78°

3 0
4 years ago
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