I strongly believe the answer is c
Hope this helps in some way:)
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
<h3>
Answer: 5</h3>
The coefficient is the term just to the left of the variable. So for the term 5y, the number to the left of y is 5.
extra info: 5y is the same as 5*y or "5 times y", where y is a placeholder for some unknown number.
Answer:
A stadium has 49000 seats.
Seats sell for $25 in Section A, z
$20 in Section B,-------------------x seats
$15 in Section C. ------------------y seats
(x+y)=z
25(x+y)+20x+15y=1052000
25x+25y+20x+15y=1052000
45x+40y=1052000
/5
9x+8y=210400------------------1
2x+2y=49000
/2
Step-by-step explanation:
When two lines meet or cross that is call intersecting
