Answer:
#include <iostream>
using namespace std;
void matrix(){
int row = 5, col = 6;
int myarr[row][col];
for (int i = 0; i < 5; i++){
for (int x = 0; x < 6; x++){
if (i == 0){
myarr[i][x] = (x+1)*(x+1);
}else if ( x == 0){
myarr[i][x] = (i+1)*(i+1)*(i+1);
} else if ( i == x){
myarr[i][x] = (i+1);
} else{
myarr[i][x] = myarr[i-1][x] + myarr[i][x-1];
}
}
}
for (int i = 0; i < 5; i++){
for (int x = 0; x < 6; x++){
cout<< myarr[i][x] << " ";
}
cout<< "\n";
}
}
int main(){
matrix();
}
Explanation:
The C++ source code defines a two-dimensional array that has a fixed row and column length. The array is a local variable of the function "matrix" and the void function is called in the main program to output the items of the array.
Answer:
int counter = 0;
String userInput = "";
while (userInput != "stop") {
print "What pet do you have? ";
userInput = readInputLine();
if (userInput != "stop" ){
counter = counter + 1;
print "\nYou have one ";
print userInput;
print ". Total # of Pets: ";
print counter;
}
}
Explanation:
not sure what programming language you use, therefore the answer is pseudocode but it should give you an idea how to implement a piece of code for this problem.
Also, from the way you described the exercise I'm not sure if you always are supposed to reply with "you have one" + the pet or if you should count how often the same pet was entered.
Answer:
When Patricia checks her email use:
POP3
TCP
IP
When Patricia brows a website and log in to post a comment use:
HTTP
TCP
IP
LDAP
Explanation:
Email protocol
Patricia starts to check her email, the email application uses the protocol POP3.
The protocol TCP makes a connection with the server and transport the data.
Patricia receives her emails with the protocol IP on her computer.
Website protocol
Patricia started to surf and the protocol HTTP makes a connection with the internet.
The protocol TCP makes a connection with the server and transport the data.
With the protocol IP, she receives the website data.
With the protocol LDAP, Patricia makes a login to post the comment.
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