The answer is a.two
In general, use no more than two font types in a worksheet.
Answer:
// here is code in c++ to find the approx value of "e".
#include <bits/stdc++.h>
using namespace std;
// function to find factorial of a number
double fact(int n){
double f =1.0;
// if n=0 then return 1
if(n==0)
return 1;
for(int a=1;a<=n;++a)
f = f *a;
// return the factorial of number
return f;
}
// driver function
int main()
{
// variable
int n;
double sum=0;
cout<<"enter n:";
// read the value of n
cin>>n;
// Calculate the sum of the series
for (int x = 0; x <= n; x++)
{
sum += 1.0/fact(x);
}
// print the approx value of "e"
cout<<"Approx Value of e is: "<<sum<<endl;
return 0;
}
Explanation:
Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".
Output:
enter n:12
Approx Value of e is: 2.71828
Answer:
B.O(1)
Explanation:
When we are implementing ADT stack using linked chain we can pop an entry from the stack having O(1) time complexity because in linked chain we have the head or top pointer in linked chain only.Popping and pushing in stack happens on only one end that is top.So we have move to move top in linked chain to the next and delete prev node.
TCP tells or state how applications can make channels of communication across a network.
<h3>What is the role of TCP?</h3>
TCP is known to often help in the management of how a message is put together into smaller packets before they are sent or transmitted over the internet and then put together again in the right way at the arriving or destination address.
Therefore, TCP tells or state how applications can make channels of communication across a network.
Learn more about TCP from
brainly.com/question/17387945
#SPJ11
Answer:
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