Answer:
Have a more specified search
Explanation:
If you do this in G0OGLE Then it will be the same thing all it basically does it narrow down the search to find more of what you want
Answer:
year = int(input("Enter a year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print(str(year) + " - leap year")
else:
print(str(year) +" - not a leap year")
else:
print(str(year) + " - leap year")
else:
print(str(year) + "- not a leap year")
Explanation:
*The code is in Python.
Ask the user to enter a year
Check if the <u>year mod 4</u> is 0 or not. If it is not 0, then the year is not a leap year. If it is 0 and if the <u>year mod 100</u> is not 0, then the year is a leap year. If the <u>year mod 100</u> is 0, also check if the <u>year mod 400</u> is 0 or not. If it is 0, then the year is a leap year. Otherwise, the year is not a leap year.
Try icthio.com I use that and its free.Good luck,!
