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notka56 [123]
3 years ago
10

The value of a dirt bike decreases by 25% each year. If you purchased this dirt bike today for $500, to the nearest dollar how m

uch would the bike be worth five years later?
Mathematics
2 answers:
Harman [31]3 years ago
5 0
First. Find out what 25% of 500 is,then minus that from 500 five times.

It wont be worth anything because it will be $-125 in 5 years.

500-125-125-125-125-125= -125
k0ka [10]3 years ago
4 0

Answer: the answer is 119

Step-by-step explanation:

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Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
How to do this in a 6th grade way
il63 [147K]

Answer:

4 2/3 - 1 2/3 and just keep doing that until you get to 0 it would take 3 days

Step-by-step explanation:

4 2/3 - 1 2/3=3

3- 1 2/3= 1 1/3

1 1/3- 1 2/3 = -1/3

6 0
3 years ago
I will give branliest to the first person to answer!
lara31 [8.8K]

Answer:

1: 10x-5

2: 6.5w-3y

3: 15+3n

4: not sure

8 0
3 years ago
True or false: you flip the sign every time you multiply or divide when you're solving an
larisa [96]

False. You only flip when the number you are multiplying/dividing is negative.

5 0
2 years ago
Divide : 5 ( 2X+1 ) ( 3X+5 ) ÷ ( 2X+1 )​
lesantik [10]

Answer:

15x+25

Step-by-step explanation:

cancel out (2x+1) you'll be left with 5(3x+5)

when multiply 5 by 3x+5

6 0
3 years ago
Read 2 more answers
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