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PIT_PIT [208]
2 years ago
7

Please i need help! :(

Mathematics
2 answers:
stepan [7]2 years ago
5 0
Help help help help help help
Shalnov [3]2 years ago
5 0
The area of The bedroom would be 30
Because the walls are a 6 by 5 and all your doing there is multiplying 6 x 5
You might be interested in
A bacteria cell splits into two cells every hour. Write and evaluate an exponential expression to find how many cells there will
ryzh [129]
Easy

equation is
f(x)=2ˣ

where x=number of hours elapsed

after 6 hours
f(6)=2⁶=64 bacteria


to solve for 1024

1024=2ˣ
take ln of both sides
ln(1024)=ln(2ˣ)
ln(1024)=x(ln(2))
divide both sides by ln(2)
ln(1024)/ln(2)=x
using calculator
10=x

or you could recognize that
1024=2¹⁰
or keep divising 1024 by 2


10 hours for 1024 bacteria

4 0
3 years ago
Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible
Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

pq =    \sqrt{( {x2 - x1)}^{2}  + ( {y2 - y1)}^{2} }

or \:  \sqrt{( {5  + 3)}^{2} + ( {2 - 2)}^{2}  }

By simplifying it we get,

8

Now,

again finding the distance between PR,

pr = \sqrt{( {x2 - x1}^{2}  + ( {y2 - y1)}^{2} }

or,

\sqrt{( {x + 3)}^{2}  + ( {y - 2)}^{2} }

By simplifying it we get,

=  \sqrt{ {x}^{2} +  {y}^{2} + 6x  -  4y + 13  }

now, finding the distance of QR,

qr =  \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2}  }

or, by simplification we get,

\sqrt{ {x}^{2} +  {y}^{2}  - 10x - 4y + 29 }

now, equating PR and QR,

\sqrt{ {x}^{2} +  {y}^{2}  + 6x  -  4y  + 13}  =  \sqrt{ {x}^{2}  +  {y}^{2} - 10x - 4y + 29 }

we cancelled the root ,

{x}^{2} +  {y}^{2} + 6x - 4y + 13 =  {x}^{2}   +  {y}^{2}   -10x - 4y + 29

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

\sqrt{ {x}^{2} +  {y}^{2}  + 6x - 4y + 13 }  =  8}

cancel the roots,

{x}^{2} +  {y}^{2}   + 6x - 4y + 13  = 8

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

<em>Hope it helps</em><em>.</em><em>.</em><em>.</em>

3 0
3 years ago
What is the equation of this trend line?
solmaris [256]

Equation of this line is K = -2J + 28

<u>Step-by-step explanation:</u>

Step 1:

The equation can be written in slope intercept form which is y = mx + b

Step 2:

Calculate slope of the line, m = (y2 - y1)/(x2 - x1)

⇒ m = (24 - 20)/(2 - 4) = 4/-2) = -2

Step 3:

Find y-intercept of the line

⇒ b = 28

Step 4:

Substitute values in the equation

⇒ K = -2J + 28

5 0
3 years ago
Can y’all help please
kirill115 [55]
SOH
Sin-1(57/100)= 34.75022575
So the answer could be 35
5 0
3 years ago
Answer quickly please &lt;3
sertanlavr [38]

Answer:

x is greater than -5

Step-by-step explanation:

3 0
3 years ago
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