we are given

now, we can compare it with

we can find b
we get

now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8

b=1.6

b=1.4

b=1.2

now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
101/32 or 3 5/32 or 3.15625
(5/4 × 54/48) = 45/32
(5/4 × 105/75) = 7/4
7/4 x 8 top & bottom =56/32
45+56=101
Hope this helps!
Answer:
one
Step-by-step explanation:
When a system of equations is graphed, the solution is the coordinate that is plotted at the intersection of the two lines.
If the two lines cross once, there is only one solution.
If the two lines are on top of each other then there are infinitely many solutions.
If the two lines are parallel ( and never touch ) then there are no solutions
By looking at the graph we notice the two lines intersect once. So we can conclude that there is only one solution.

∠ Given are (x + 18)° , x° , 4x° and one Angle is 90° as per diagram
Let ,
1st∠ = (x + 18)°
2nd∠ = x°
3rd∠ = 4x°
so ,

substituting x = 12 at the place of x .
= x° + 18°
= 12° + 18 °
1st∠ = 30°
__________________________________
= x°
2nd∠ = 12°
__________________________________
= 4x°
= 4(12)°
3rd∠ = 48°