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Rama09 [41]
2 years ago
13

What is the missing dimention with a cilinder with base as d and the height as 14 and it has a volume of 7433 in 3

Mathematics
1 answer:
Korolek [52]2 years ago
4 0

Answer:

26in

Step-by-step explanation:

Volume of a cylinder = πr²h

Given

height h = 14in

Volume = 7433in³

Required

base d = 2r

r is the  radius

get the radius r

7433 = 3.14 * 14r²

7433 = 43.96r²

r² = 7433/43.96

r² = 169.08

r = 13.00

Since the base d = 2r

d = 2(13)

d = 26in

Hence the base of the cylinder is 26in

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The equation would be 9 * 2 = 18

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The ratio of the side lengths for a triangle is exactly 9:12:15. In another triangle, which is similar to the first, the shortes
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Are 5.5 + 2.1x + 3.8x - 4.1 and 1.4 5.9x equivalent
Marat540 [252]

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6 0
3 years ago
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An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

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Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

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6 0
3 years ago
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