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Alex
4 years ago
12

Factor 4x^2+81 over the set of complex numbers.

Mathematics
1 answer:
Hunter-Best [27]4 years ago
3 0

Use:\\\\i=\sqrt{-1}\to i^2=-1\\\\a^2-b^2=(a-b)(a+b)\\--------------------\\\\4x^2+81=2^2x^2+9^2=(2x)^2-(-9^2)=(2x)^2-(-1)(9^2)\\\\=(2x)^2-(i^2)(9^2)=(2x)^2-(9i)^2=\boxed{(2x-9i)(2x+9i)}

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What is the solution set for -4x-10 ≤ 2?
SashulF [63]

Answer:

x≥−3

Step-by-step explanation:

Let's solve your inequality step-by-step.

−4x−10≤2

Step 1: Add 10 to both sides.

−4x−10+10≤2+10

−4x≤12

Step 2: Divide both sides by -4.

−4x /−4 ≤ 12 /−4

= x≥−3

<h3><em><u>brainliest please?</u></em></h3>
5 0
3 years ago
Read 2 more answers
Patty bought a "P" poster to put on her wall, as shown below.
kolezko [41]

The area of the poster is B. 535.5 in².

Step-by-step explanation:

Step 1:

The poster consists of a rectangle and three-quarters of a circle.

The rectangle has a length of a and width of 3a. The circle has a radius of a.

We calculate the areas of the individual shapes and sum them up to calculate the entire area of the poster.

Step 2:

The area of a rectangle is the product of its length and its width.

If a = 10 inches, the length is 10 inches and the width is 30 inches.

The area of the rectangle = (l)(w) = (10)(30)= 300.

The area of the rectangle is 300 in².

Step 3:

The area of a circle = \pi r^{2} . Here we only have three-quarters of a circle, so

The area of the given circle =\frac{3}{4} ( \pi r^{2} ).

Here r = a = 10 inches.

So the area of the circle =\frac{3}{4} ((3.1415) (10^{2}) ) = 235.6125.

The area of the circle is 235.6125 in².

Step 4:

The total area of the shape = The area of the rectangle + The area of the circle.

The total area of the shape = 300 + 235.6125 = 535.6125.

So the area of the poster is B. 535.5 in².

7 0
3 years ago
PLEASEEE HELP I WILL GIVE U BRAIN THING IF ITS CORRECT
sweet [91]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Find the measure of angle b
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Answer:

32 degrees

Step-by-step explanation:

Makes sense. Brainlist me if I'm right

5 0
3 years ago
What is the volume of a box that can fit exactly 128 1/8 inch cubes with 1/2 inch sides?
swat32
\bf \textit{the volume of one small cube is }V=\left( \frac{1}{2} \right)\left( \frac{1}{2} \right)\left( \frac{1}{2} \right)\implies V=\cfrac{1}{8}&#10;\\\\\\&#10;\textit{now, the box fits in }128\frac{1}{8}\textit{ of those cubes, thus its volume is}&#10;\\\\\\&#10;128\frac{1}{8}\cdot \cfrac{1}{8}\implies \cfrac{128\cdot 8+1}{8}\cdot \cfrac{1}{8}\implies \cfrac{1025}{8}\cdot \cfrac{1}{8}\implies \cfrac{1025}{64}\implies 16\frac{1}{64}~in^3
3 0
3 years ago
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