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VARVARA [1.3K]
3 years ago
11

Help me out plz it’s due rn

Mathematics
2 answers:
IRISSAK [1]3 years ago
7 0

Answer:

x= square root (10); x=-square root (10) or 3.16 and -3.16

Step-by-step explanation:

MatroZZZ [7]3 years ago
5 0

Answer:

Step-by-step explanation:

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Proportionality math
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no bc the graph shows a slope of 12

Step-by-step explanation:

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The bulletin board is in the shape of a square. Find two rational numbers that are within 1/8 in of the actualy side length.
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16 because it iscvbnmvcxcvbnmvcxcvbnm,
7 0
3 years ago
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A triangle with equal sides and a square have the same perimeters. The length of a side of the triangle is 2x + 2. The length of
andreev551 [17]

Answer:

x=13

Step-by-step explanation:

3(2x+2)=4(x+8)\\6x+6=4x+32\\2x+6=32\\2x=26\\x=13

3 0
3 years ago
According to the synthetic division below, which of the following statements are true? Check all that apply. -5(2 6 -8) -10 20 _
Sunny_sXe [5.5K]
***(2x²+6x-8):(x+5)=2x-4
     -2x²-10x
    ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
         -4x-8
          4x+20
    ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
              12 ⇒ A. statement is true.

***When x=-5⇒2*(-5)²+6*(-5)-8=12⇒B. statement is true.

***2x²+6x-8 can also be written as (x+5)*(2x-4)+12 so (x+5) is a factor of 2x²+6x-8⇒C. statement is true.

***When x=5⇒2*5²+6*5-8=72 is not 12⇒D. statement is not true

***
(2x²+6x-8):(x+5)=2x+16
     -2x²+10x
    ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
              16x-8
             -16x+80
        ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
                     72⇒F. statement is not true

**
*E. statement is not true.





8 0
3 years ago
Read 2 more answers
jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i
FrozenT [24]

Answer:

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length  and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is    2(x +y) = 80

                         x + y =40

                               y = 40 -x

now the area of the rectangle A = length X width

                                                  A = x y

substitute 'y' value in above A = x (40 - x)

                                              A = 40 x - x^2 .....(1)

<u>Step :2</u>

now differentiating equation (1) with respective to 'x'

                                      \frac{dA}{dx} = 40 -2x     ........(2)

<u>Find the dimensions</u>

<u></u>\frac{dA}{dx} = 0<u></u>

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

<u>Step 3</u>:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

\frac{d^2A}{dx^2} = -2

Now the maximum area A =  x y at x =20 and y=20

                                        A = 20 X 20 = 400

                                         

<u>Conclusion</u>:-

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

<u>verification</u>:-

The perimeter = 2(x +y) =80

                           2(20 +20) =80

                              2(40) =80

                              80 =80

8 0
3 years ago
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