Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
10^3 CDs with CD = $12 then total CDs earnings is (10^3)(12) = $12,000
10^2 CD players with CD plater = $35 then total CD player earnings is (10^2)(12) = $1,200
Total store earnings = ($12,000 + $1,200) = $13,200
It should open up because the a which is 4 is positive
we are given with the inequality

Open the parenthesis we get on left side we get

Answer:
3.5
Step-by-step explanation:
35/10 = 3.5