Answer:
The width of the red tile would be 
inches.
Step-by-step explanation:
Given blue tile has a length of 
inches, and a width of 
inches.
Also, length of similar tile is 
inches.
Let us assume 
as the width of red tile.
It is given in the question that both tiles are similar.
So, their area will be the same.
Area of blue tile would be 
Area of red tile would be 
The area of blue tile would be equal to area of red tile.
So, the width of the red tile would be inches.
We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).
140 if I observed the image correctly.
Answer:
f=9 x 20
Step-by-step explanation:
