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2 years ago

What is f(-3) if f(x) = 12x + 1] + 5? Α. 0 B. 10 C. 12 D. -10

Mathematics

1 answer:

alexgriva [62]2 years ago

3 0

Use the given functions to set up and simplify
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35

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Which would best display the following data if you wanted to display the numbers which are outliers as well as the mean? [4, 1,

Serhud [2]

Arranging data in ascending order to identify the outlier and calculate the mean

Step-by-step explanation:

Given the data as: [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32]

Arrange in ascending order

[1, 3, 4, 4, 9, 10, 12, 15, 16, 18, 32 ]

The outlier is 32

Finding the mean;

Mean=sum of data set/number of data set

Sum= 1 + 3+ 4+ 4+ 9+ 10+ 12+ 15+ 16+ 18+ 32=124

Number of data set=11

Mean=124/11=11.27

Learn More

Outliers: brainly.com/question/12612191

Keywords: display,data, numbers,outliers,mean

#Learnwithbrainly

3 0

2 years ago

Describe how to transform the quantity of the fifth root of x to the seventh power, to the third powerinto an expression with a

geniusboy [140]

$(\sqrt[5]{x^{7}})^{3}=(x^{\frac{7}{5}})^{3}=x^{\frac{7\cdot3}{5}}=x^{\frac{21}{5}}$

The root is equivalent to a fractional power with that number as the denominator. Otherwise, the rules of exponents apply.

7 0

3 years ago

Last year, a person wrote 126 checks. Let the random variable x represent the number of checks he wrote in one day, and assume

Arisa [49]

Answer: The mean number of checks written per day $=0.3452$

Standard deviation $=0.5875$

Variance $=0.3452$

Step-by-step explanation:

Given : The total number of checks wrote by person in a year = 126

Assume that the year is not a leap year.

Then 1 year = 365 days

Let the random variable x represent the number of checks he wrote in one day.

Then , the mean number of checks wrote by person each days id=s given by :-

$\lambda=\dfrac{126}{365}\approx0.3452$

Since , the distribution is Poisson distribution , then the variance must equal to the mean value i.e. $\sigma^2=\lambda=0.3452$

Standard deviation : $\sigma=\sqrt{0.3452}=0.5875372328\approx0.5875$

6 0

3 years ago

Please help I'll give brainliest

Hoochie [10]

You have to multiply by how many months or boxes and your gonna have 360 and your friend 288

5 0

2 years ago

3. (6 Points). Solve the initial value problem y'-y.cosx=0, y(pi/2)=2e

Stells [14]

Answer:

$y=2e^{sin(x)}$

Step-by-step explanation:

Given equation can be re written as

$\frac{\mathrm{d} y}{\mathrm{d} x}-ycos(x)=0\\\frac{\mathrm{d} y}{\mathrm{d} x}=ycos(x)\\\\=> \frac{dy}{y}=cox(x)dx\\\\Integrating \\ \int \frac{dy}{y}=\int cos(x)dx \\\\ln(y)=sin(x)+c$ ............(i)

Now it is given that y(π/2) = 2e

Applying value in (i) we get

ln(2e) = sin(π/2) + c

=> ln(2) + ln(e) = 1+c

=> ln(2) + 1 = 1 + c

=> c = ln(2)

Thus equation (i) becomes

ln(y) = sin(x) + ln(2)

ln(y) - ln(2) = sin(x)

ln(y/2) = sin(x)

$y= 2e^{sinx}$

7 0

2 years ago