All categories

3 years ago

The percent of increase or decrease i. this irem

Mathematics

1 answer:

Nikolay [14]3 years ago

3 0

Since the price is going down, it's going to be a percent decrease. Now to find the percent, we divide the "after" price by the "before" price.

240 / 320 = 0.75 = 75%

The item had a 75% decrease.

You might be interested in

Solve the inequality for x: -3(2x+5) < -45

balandron [24]

Answer:

x>5

Step-by-step explanation:

-3(2x+5)<-45

2x+5<-45/-3

2x+5<15

2x<15-5

2x<10

x<10/2

x<5

x>5

7 0

3 years ago

The cost of 4 belts and 5 ties is $247. Each time costs 3 times as much as a belt. What us the total cost of 1 belt and 1 tie

Makovka662 [10]

Answer:

The total cost of 1 belt and 1 tie is $13 and $39 respectively.

Step-by-step explanation:

Given that,

The cost of 4 belts and 5 ties is $247.

Each tie costs 3 times as much as a belt.

Let the cost of a belt is x and that of a tie is y.

ATQ,

4x + 5y = 247 ...(1)

y = 3x ....(2)

Put the value of y from equation (2) in equation (1)

4x + 5(3x) = 247

4x + 15x = 247

19x = 247

x = 13

Put the value in equation (2)

y = 3x

= 3(13)

= 39

So, the total cost of 1 belt and 1 tie is $13 and $39 respectively.

5 0

3 years ago

If your character in your favorite game get 5 EXP after defeating a normal monster and there are 50 monsters much EXP will he ga

Lerok [7]

Answer:

5 EXP x 50 Monsters = 250 EXP

Step-by-step explanation:

6 0

3 years ago

There are 250 economy class seats on board. The airline sells some economy class seats at a discount price of $440 in advance an

Drupady [299]

Answer:

Check the explanation

Step-by-step explanation:

Cost of over reserving full cost tickets, Co = $440 ( empty seats as we cannot get even the discounted revenue)

Cost of under reserving Cu = 770-440 = $330 ( because you sell more discounted tickets)

Now critical ratio = Cu / (Cu+Co) = 330/770 = 0.42857

Now for above critical ratio ,z = -0.18 ( refer standard normal distribution table)

Optimal protection level = mean +z*standard deviation = 100-0.18*25 = 95.5 = 96

The possible costs include: all the above. You may need to provide compensation to passenger and make alternative travel arrangements. Also passenger won't be happy by over booking and their will be loss of good will.

3 0

3 years ago

A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and

pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean $\mu$ and standard deviation $\sigma$ , we have these following probabilities

$Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827$

$Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545$

$Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973$

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So $\mu = 53, \sigma = 11$

So:

$Pr(53-11 \leq X \leq 53+11) = 0.6827$

$Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545$

$Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973$

-----------

$Pr(42 \leq X \leq 64) = 0.6827$

$Pr(31 \leq X \leq 75) = 0.9545$

$Pr(20 \leq X \leq 86) = 0.9973$

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have $Pr(31 \leq X \leq 75) = 0.9545 = 0.9545$ subtracted by $Pr(42 \leq X \leq 64) = 0.6827$ is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

$P = {0.9545 - 0.6827}{2} = 0.1359$

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0

3 years ago