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Kobotan [32]
3 years ago
7

The initial count of a certain type of bacteria in a culture is 350. If the bacteria grows at the rate of 20% per hour, which fu

nction models the number of bacteria after t hours?
Mathematics
2 answers:
Irina-Kira [14]3 years ago
8 0

I’m not sure but I put f(t)=350e^(1+0.2t)

raketka [301]3 years ago
4 0
I think it is 350(1.2)^t because you take the starting amount (350) and then multiple it by the growth rate (which is 20%, but when added to 100 and the put into a decimal is 1.2) raised by the number of hours (t).
I hope this helps.
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Step-by-step explanation:

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Which of the following describes the sum in terms of p and q?(1 point)
snow_tiger [21]

The description of the summation expression given as p + (-q) is the sum, p + (-q), is the number located a distance, |p|, from , q, in the negative direction.

<h3>How to describe the sum in terms of p and q?</h3>

The summation expression is given as:

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In the above summation expression, we assume that:

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Having said that:

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This means that the description of the summation expression given as p + (-q) is the sum, p + (-q), is the number located a distance, |p|, from , q, in the negative direction.

Hence, the description of the summation expression given as p + (-q) is the sum, p + (-q), is the number located a distance, |p|, from , q, in the negative direction.

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6 0
1 year ago
Use the sum and difference identities to find the exact values of the sine, cosine, and tangent of the angle. . 165 = 135 + 30
Serhud [2]
So lets get to the problem 

<span>165°= 135° +30° </span>

<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>

<span>Sin165° </span>
<span>= Sin ( 90° + 45°+30° ) </span>
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<span>= Cos45°Cos30° - Sin45°Sin30° </span>

<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
<span>= -Sin( 45°+30° )..... (∵Cos(90 + θ)=-Sinθ </span>
<span>= Sin45°Cos30° + Cos45°Sin30° </span>


<span>Tan165° </span>
<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
<span>= -1/tan(45°+30°) </span>
<span>= -[1-tan45°.Tan30°]/[tan45°+Tan30°] </span>

<span>Substitute the above values with the following... These should be memorized </span>
<span>Sin 30° = 1/2 </span>
<span>Cos 30° =[Sqrt(3)]/2 </span>
<span>Tan 30° = 1/[Sqrt(3)] </span>
<span>Sin45°=Cos45°=1/[Sqrt(2)] </span>
<span>Tan 45° = 1</span>
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