Answer:
This is khan academy. I am pretty sure they have a video for this but whatever.
Step-by-step explanation:
So we are using sin, cosine, and tan. 3.4 is the hypotenuse. the side is X. The angle is 20 degrees. So, this is adjacent to hypotenuse. This means it is cosine.
3.4cos(20)= around 3.19
And thats that! let me know if this is wrong and I will try to fix it.
Answer:
a+2b-d=1, 3, 5, 7
Step-by-step explanation:
(ax^2+bx+3)(x+d)
ax^3+bx^2+3x+adx^2+bdx+3d
ax^3+bx^2+adx^2+3x+bdx+3d=x^3+6x^2+11x+12
ax^3=x^3, a=1
bx^2+adx^2=6x^2
x^2(b+ad)=6x^2
b+ad=6
b+(1)d=6
b+d=6
------------
3x+bdx=11x
x(3+bd)=11x
3+bd=11
-----------------
b=6-d
3+(6-d)d=11
3+6d-d^2=11
3-11+6d-d^2=0
-8+6d-d^2=0
d^2-6d+8=0
factor out,
(d-4)(d-2)=0
zero property,
d-4=0, d-2=0
d=0+4=4,
d=0+2=2
b=6-4=2,
b=6-2=4.
------------------
a+2b-d=1+2(2)-2=1+4-2=5-2=3
-------------------
a+2(4)-4=1+8-4=9-4=5
-----------------------
a+2(2)-4=1+4-4=5-4=1
-----------------------
a+2(4)-2=1+8-2=9-2=7
Solution
To find Which two numbers on the number line has an
absolute value of 3
Absolute value means " how far a number is from
zero " .
"3" is 3 away from zero .
and " -3 " is also 3 away from zero .
i.e
| 0 - 3 | = 3
| 3 - 0 | = 3
So , the absolute value of "3 " is 3
similarly , absolute value of "3 " is 3 .
Hence , the two numbers are -3 and 3
Answer:
9.9
use the special triangle formula or use cosine to find BC
2x+12 would be the answer
