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Len [333]
3 years ago
7

What graph matches the related tables ? And please explain why !!!

Mathematics
2 answers:
alina1380 [7]3 years ago
7 0

Graph 1 is related to table C because the first 3 values are increasing, and the 4th value decreases. Or because at 1PM, 3PM, and 5PM, the temperature was increasing, but at 7PM the temperature decreased. Graph 1 shows the first 3 points increasing, and then decreasing at the 4th point.


Graph 2 is related to table A because as the time increases/goes on, the temperature decreases exponentially/continues to decrease at a higher rate than before. From 1-3PM the temperate decreases by 2°F, from 3-5PM it decreased by 8°F, from 5-7PM the temperature decreased by 17°F.


Graph 3 is related to table B because as the time increases/goes on, the temperature decreases at a steady rate of 1°F every 2 hours.

Irina18 [472]3 years ago
7 0
The answer would be c
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Answer:

<h3>40 degrees</h3>

Step-by-step explanation:

If the temperature dropped 5 degrees every hour, this can be expressed as;

5 degree = 1 hour

To get the total number of degree dropped fro 8hours, we will say;

x degree = 8hours where x is the temperature drop in all

Solving both equality

5 degree = 1 hour

x degree = 8 hours

cross multiply

x * 1 = 5 * 8

x = 40 degrees

<em>Hence the total temperature drop in all is 40°</em>

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4 years ago
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D 3:4

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{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

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\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

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[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

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\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

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• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

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