X+2/4 = 3/8 solve for x
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The remaining balances in the first and second account are $5805 and $1020 respectively.
<em><u>Explanation</u></em>
Suppose, the initial balance in the first account was dollar.
As the total amount in two accounts was $9000, so the <u>initial balance in the second account was</u>
He withdrew 10% from the first and 60% from the second account to buy the ring which cost $2175. So, the equation will be......
So, <u>the initial balance</u> in the first account was $6450 and in the second account was ($9000 - $6450)= $2550
Thus, the remaining balance in the first account = 90% of $6450 =
and the remaining balance in the second account = 40% of $2550 =