The solutions to the given inequalities are x < 6 OR x < -10
<h3>Linear Inequalities </h3>
From the question, we are to solve the given inequalities
The given inequalities are
6x - 4(2x - 5) > 8 or 5x + 9 < 2x - 21
First solve,
6x - 4(2x - 5) > 8
Clear the bracket
6x -8x + 20 > 8
6x - 8x > 8 - 20
-2x > -12
Divide both sides by -2 and flip the sign,
That is,
-2x/-2 > -12/-2
x < 6
For,
5x + 9 < 2x - 21
Subtract 2x from both sides
5x - 2x + 9 < 2x - 2x -21
3x < -21 -9
3x < -30
Divide both sides by 3
3x/3 < -30/3
x < -10
Hence, the solutions to the given inequalities are x < 6 OR x < -10
Learn more on Inequalities here: brainly.com/question/246993
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Answer:
83 adult tickets and 217 student tickets.
Step-by-step explanation:
Let number of adult tickets sold = 
Given that total number of tickets = 300
So, number of student tickets = 300 - 
Cost of adult ticket = $15
Cost of student ticket = $11
Total collection from adult tickets = $
Total collection from student tickets = 
Given that overall collection = $3630

So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.
Now , collection = $3632
10 3/5=10.6
10.6+12.5=23.1
35.0-23.1=11.9
It is 11.9 miles from Chester to Durbin.
30° the angle is ro small to be 90° to small to be 60° and to small to be 120°
Since you gave no parenthesis: Remember to follow PEMDAS. Note that anything with the power of 0, the answer will become 1
10^0 = 1
8 x 1 = 8
8 is your answer
hope this helps