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Vladimir79 [104]
3 years ago
6

The sum of the measures of two complementary angles exceeds the difference of their measures by72°. Find measure of the smaller

angle
Mathematics
1 answer:
weqwewe [10]3 years ago
3 0

Answer: 18


Step-by-step explanation:

this is because complementary angles add up to 90 degrees so you would just subtract 72 from 90 to get your answer :)

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PRETTY PLEASE HELP!! ILL GIVE BRAINLIEST! it’s due tonight :(
Marianna [84]

Answer:

a = 8 m

Step-by-step explanation:

Since, given is an isosceles right triangle.

So, by Pythagoras theorem:

{a}^{2}  +  {a}^{2}  =  {(8 \sqrt{2} )}^{2}  \\  \\ 2 {a}^{2}  = 128 \\  \\  {a}^{2}  =  \frac{128}{2}  \\  \\  {a}^{2}  = 64 \\  \\ a =  \sqrt{64}  \\  \\ a = 8 \: m

5 0
3 years ago
Quadrilateral RJFT is similar to quadrilateral SYPA . JF=60 mm , AP=40 mm , and YP=25 mm . What is TF ?
Hoochie [10]
The two quadrilaterals are similar. Which means the ratios of respective sides of two quadrilaterals will be the same. 

So, for the given quadrilaterals, ratio of sides JF and TF of quadrilateral RJFT will be equal to the ratio of sides YP and AP of quadrilateral SYPA. Mathematically, we can write:

JF:TF = YP:AP \\  \\ 
 \frac{JF}{TF} = \frac{YP}{AP}  \\  \\ 
 \frac{60}{TF} = \frac{25}{40}  \\  \\ 
60* \frac{40}{25}=TF \\  \\ 
TF=96mm

So the measure of TF will be 96mm
7 0
3 years ago
Rationalise the denominator of: (√3 + √2)/(√3-√2) = ?<br>​
krok68 [10]

Step-by-step explanation:

<h3><u>Given</u><u>:</u><u>-</u></h3>

(√3+√2)/(√3-√2)

<h3><u>To </u><u>find</u><u>:</u><u>-</u></h3>

<u>Rationalised</u><u> form</u><u> </u><u>=</u><u> </u><u>?</u>

<h3><u>Solution</u><u>:</u><u>-</u></h3>

We have,

(√3+√2)/(√3-√2)

The denominator = √3-√2

The Rationalising factor of √3-√2 is √3+√2

On Rationalising the denominator then

=>[(√3+√2)/(√3-√2)]×[(√3+√2)/(√3+√2)]

=>[(√3+√2)(√3+√2)]×[(√3-√2)(√3+√2)]

=>(√3+√2)²/[(√3-√2)(√3+√2)]

=> (√3+√2)²/[(√3)²-(√2)²]

Since (a+b)(a-b) = a²-b²

Where , a = √3 and b = √2

=> (√3+√2)²/(3-2)

=> (√3-√2)²/1

=> (√3+√2)²

=> (√3)²+2(√3)(√2)+(√2)²

Since , (a+b)² = a²+2ab+b²

Where , a = √3 and b = √2

=> 3+2√6+2

=> 5+2√6

<h3><u>Answer:-</u></h3>

The rationalised form of (√3+√2)/(√3-√2) is 3+2√6+2.

<h3><u>Used formulae:-</u></h3>

→ (a+b)² = a²+2ab+b²

→ (a-b)² = a²-2ab+b²

→ (a+b)(a-b) = a²-b²

→ The Rationalising factor of √a-√b is √a+√b

8 0
3 years ago
Strands Copper wire from a manufacturer are analyzed forstrenghth and conductivity. The Results from 100 strands are asfollows:S
Thepotemich [5.8K]

Answer and explanation:

Given : Strands Copper wire from a manufacturer are analyzed forstrenghth and conductivity. The Results from 100 strands are as follows :

                                                 Strength Strength

                                                    High             Low

High conductivity                         74                8

Low conductivity                         15                3

To find :

a) If a stand is randomly selected, the probability that is conductivity is high and its strength is high

The favorable outcome is 74

The probability is given by,

P=\frac{74}{100}=0.74

b) If a stand is randomly selected, the probability that its conductivity is low or  strength is low

Conductivity is low A= 15+3=18

Strength is low B= 8+3=11

Conductivity is low and  strength is low A\cap B=3

Probability is given by,

P(A\cup B)=P(A)+P(B)-P(A\cap B)

P(A\cup B)=\frac{18}{100}+\frac{11}{100}-\frac{3}{100}

P(A\cup B)=0.18+0.11-0.03

P(A\cup B)=0.26

c) Consider the event that a strand low conductivity and the event that the strand has a low strength. Are these tow events mutually exclusive?

Since the events the stand has low conductivity and the stand has low strength  are not mutually exclusive, since there exists some cases in which both the  events coincide. i.e. Intersection of both the events exists with probability 0.03.

8 0
3 years ago
The parabola with equation $y=ax^2+bx+c$ is graphed below:
Mashutka [201]

Answer:

m-n=2

Step-by-step explanation:

Instead of using the standard form, we can use the vertex form of a quadratic equation:

f(x)=a(x-h)^2+k

Where a is the leading coefficient, and (h, k) is our vertex.

Our vertex point is at (2, -4). So, let’s substitute 2 for h and -4 for k:

f(x)=a(x-2)^2-4

Now, we need to determine a.

We know that it passes through the point (4, 12). So, when x is 4, y must be 12. In other words:

12=a((4)-2)^2-4

Solve for a. Subtract within the parentheses:

12=a(2)^2-4

Add 4 to both sides:

16=a(2)^2

Square:

16=4a

Solve:

a=4

Thererfore, the value of a is 4.

So, our function is:

f(x)=4(x-2)^2-4

Now, let’s find our roots. Set the equation to 0 and solve for x:

0=4(x-2)^2-4

4=4(x-2)^2\\1=(x-2)^2\\x-2=\pm1 \\ x=2\pm1 \\ x=3\text{ or } 1

So, our roots are 1 and 3.

The greater root is 3 and the lesser root is 1.

Therefore, m-n, where m>n, is 3-1 or 2.

Our final answer is 2.

4 0
3 years ago
Read 2 more answers
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