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2 years ago

9.4 rounded to the nearest tenths

Mathematics

2 answers:

Julli [10]2 years ago

8 0

The answer is going to be 9

myrzilka [38]2 years ago

7 0

it would be the same bc u don't have the hundredths in the equation of the number

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The circumference of the smaller circle is 30% of the circumference of the larger circle. Find the circumference of the larger c

Tasya [4]

Answer:

The circumference of the larger circle is 94.2 inches.

Step-by-step explanation:

8 0

1 year ago

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What is the value of m in the ecuation 1/2m -3/4n = 16, when n =8 ?

soldi70 [24.7K]

Answer: m=44

Step-by-step explanation:

1/2m-3/4n = 16

1/2m-3/4(8) = 16

1/2m-24/4 = 16

1/2m-6 = 16

1/2m = 22

m=44

8 0

1 year ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

2 years ago

Find three consecutive odd numbers whose sum is 303

CaHeK987 [17]

$n;\ n+2;\ n+4-three\ consecutive\ odd\ numbers\\\\n+(n+2)+(n+4)=303\\\\3n+6=303\\\\3n=303-6\\\\3n=297\ \ \ \ /:3\\\\n=99\\\\Answer:99;\ 101;\ 103.$

8 0

2 years ago

Read 2 more answers

The mode of the data above is 6

nordsb [41]

I was stuck on the same thing in my class test. I ended up failing but if I get the answers to it I’ll totally send them to you

7 0

2 years ago