Answer:
Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .
Step-by-step explanation:
We are given that let X be the number that do some or all of their banking on the Internet.
Also; Mean,
= 310/1000 or 0.31 and Standard deviation,
= 14.63/1000 = 0.01463 .
We know that Z =
~ N(0,1)
Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);
P(X <=0.13) = P(
<=
) = P(Z <= -12.303) = P(Z > 12.303)
Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.
So, after seeing the table we can say that this probability is approximately less than 0.0005% .
The answer to 9+10 is 19 because if you add 9 to the number 10, you get 19
AE is about half of AC. What I did was get half of 28, which is 14, and represented one of the numbers.
3 x 7 = 21 - 7 = 14
It is D.
(I don't know for sure if this is right, but I did the best I could)
So, for number 3, its 2. and for number 4 its also 2