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TEA [102]
2 years ago
11

ME DONT GET IT CAN SOMEONE HELP ME

Mathematics
1 answer:
tester [92]2 years ago
6 0

put it a little bit to the right

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Maths watch homework help please​
pychu [463]

Answer:15m on each side

Step-by-step explanation:

7 0
3 years ago
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if x/b-c=y/c-a=z/a-b, prove that x+y+x=0.please help me ... this is my homework. I will follow you plz . anyone.​
irinina [24]

Answer:

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4 0
3 years ago
Transform the equation to isolate x: ax=bx+1. How is the value of x related to the difference of a and b
nasty-shy [4]

Answer:

x is the reciprocal of the difference of a and b.

Step-by-step explanation:

ax=bx+1

Subtract by bx on both sides

ax-bx=1

x(a-b)=1

x= 1/(a-b)

8 0
2 years ago
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100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
3 years ago
Please help!!!! With this problem
aleksley [76]
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