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3 years ago

Help explain for brainlist

Mathematics

2 answers:

Lina20 [59]3 years ago

7 0

Answer:

C. 8

Step-by-step explanation:

$\because \: {s}^{3} = 64 \\ s = \sqrt[3]{64} \\ s = 4 \\ side \: of \: cube = 4 \: units \\ when \: side \: is \: halved \\ new \: side \: length = \frac{4}{2} = 2 \\ \: new \: volume = {2}^{3} = 8 \: cubic \: units$

lorasvet [3.4K]3 years ago

5 0

Hi the answer is c hope this helps

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The surface area of a cube is found using the formula sa=6s^2, where s is theside length if the surface area of a cube is 294 sq

aleksley [76]

6s^2 = 294
Solve for s

Solve for s:
6 s^2 = 294
Divide both sides by 6:
s^2 = 49
Take the square root of both sides:
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8 0

3 years ago

Read 2 more answers

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: ( $a = 1$ , $b = -1$ , $c = 4$ )

$D = b^{2}-4\cdot a\cdot c$

$D = (-1)-4\cdot (1)\cdot (4)$

$D = -17$ (Conjugated complex roots)

Step E

$(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0$

Step F

$x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936$

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3 years ago

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