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IceJOKER [234]
3 years ago
14

Helllppppp please with my math I am in 7th grade

Mathematics
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer:

135.02

Step-by-step explanation:

C = 3.14 x 43

C = 135.02

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Which statement is true about numbers to the left of 0 on a number line?
NemiM [27]

Answer:

Numbers to the left of 0 on a number line or anywhere are always negative,

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
How do you solve f(x)= 4x(2)-4x-3?
slavikrds [6]
If by 4x(2) you mean 4x to the power 2 or 4x^2...it can be solved in the following way
f(x)=4x^2-4x-3
=4x^2+2x-6x-3
=2x(2x+2)-3(2x+2)
=(2x-3)(2x+2)
Therefore x=3/2 or x=-2/2=(-1)
8 0
3 years ago
I need help with no.7
ziro4ka [17]

Answer:

  (a) 315°

  (b) 3°

  (c) 238°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

<h3>(a)</h3>

The bearing of P from R is 180° different from the bearing of R from P it will be ...

  135° +180° = 315° . . . . bearing of P from R

__

<h3>(b)</h3>

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

  315° +48° = 363°, or 3° . . . . bearing of Q from R

__

<h3>(c)</h3>

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

  180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

  135° -77° = 58°

As above, the reverse bearing from Q to P is ...

  58° +180° = 238° . . . . bearing of P from Q

8 0
3 years ago
Make v the subject of the formula T = v/6 -5
OverLord2011 [107]

Answer:

Step-by-step explanation:

T=V/6-5

T+5=V/6

6(T+5)=V

V=6T+30

8 0
2 years ago
The radius of a cylinder gift box is box is 3X +1 inches the height of the gift box is twice the radius what is the surface area
Genrish500 [490]

Answer:

The surface area of the gift box is = A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

Step-by-step explanation:

The surface area of the cylinder can be calculated using this formula:

A=2\pi rh+2\pi r^2

in this case, r is not a number, but rather an expression, which is r = 3x +1.

The height of the gift box is twice the radius, which is h = 2(3x+1)= 6x+2

To get our curved surface area, we carefully put the expressions for h and r into the equation.

A = 2 \times \frac{22}{7} \times (3x+1) \times (6x+2) + 2 \times \frac{22}{7} \times (3x+1)^{2}

A = \frac{44}{7} (3x+1) \times (6x +2) + \frac{44}{7} (9x^{2} + 6x +1)\\A =\frac{132}{7}x + \frac{44}{7} \times (6x+2)+ \frac{396}{7}x^{2}+\frac{246}{7}x +\frac{44}{7}

A = \frac{792}{7}x^{2} +\frac{264}{7}x +\frac{264}{7}x + \frac{88}{7} + \frac{396}{7}x^{2} + \frac{246}{7}x + \frac{44}{7}

A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

The surface area of the gift box is = A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

5 0
4 years ago
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