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vazorg [7]
3 years ago
8

Patrick is paid $12 for 3 hours of work How many hours does she work is she gets payed $1

Mathematics
2 answers:
Oduvanchick [21]3 years ago
4 0

Answer:

Step-by-step explanation:

chubhunter [2.5K]3 years ago
4 0

Answer:

0.25 Hours or 15 minutes

Step-by-step explanation:

Please give me brainliest

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a company charges a shipping fee that is 4.5% of the purchase price for all items at ships.what is the fee to ship an item that
Pavlova-9 [17]

Answer:

The answer is $2.52.

Step-by-step explanation:

56 x .045= $2.52

6 0
3 years ago
What is the product? One-eighth times three-elevenths 3 over 88 1 over 22 4 over 19 35 over 88
kipiarov [429]

Answer:

\frac{3}{88}

Step-by-step explanation:

Given

One-eighth times three-elevenths

Required

Solve

One-eighth means 1/8

Three-elevenths means 3/11

So, mathematically; the above expression is represented as thus:

\frac{1}{8} * \frac{3}{11}

To solve this, we simply multiply the numerator and the denominator together.

After multiplying these together, the next is to check if the resulting can be simplified

If yes,we simplify it and if otherwise, we live it like that.

So,

\frac{1}{8} * \frac{3}{11}

=\frac{1 * 3}{8 * 11}

= \frac{3}{88}

At this point, the fraction can't be simplified any further.

Hence,

\frac{1}{8} * \frac{3}{11} = \frac{3}{88}

3 0
3 years ago
HELP QUICK PLS!
RoseWind [281]
C), cause you would subtract 5 from 53 in order to move it, and would get 6x=48. Then, you would divide by six on both sides, and the answer would be x=8, so Number C.
6 0
3 years ago
Read 2 more answers
Doug has $12 to spend on popcorn and peanuts. The peanuts are $4 each and popcorn is $2 each Write a linear equation that descri
Fynjy0 [20]
Popcorn=x
peanuts=y
2x+4y=12
4 0
3 years ago
In 1981, the Australian humpback whale population was 350 and has increased at a rate of 14% each year since then.)
dimulka [17.4K]

Answer:

In 1981, the Australian humpback whale population was 350

Po = Initial population = 350

rate of increase = 14% annually

P(t) = Po*(1.14)^t

P(t) = 350*(1.14)^t

Where

t = number of years that have passed since 1981

Year 2000

2000 - 1981 = 19 years

P(19) = 350*(1.14)^19

P(19) = 350*12.055

P(19) = 4219.49

P(19) ≈ 4219

Year 2018

2018 - 1981 = 37 years

P(37) = 350*(1.14)^37

P(37) = 350*127.4909

P(37) = 44621.84

P(37) ≈ 44622

There would be about  44622  humpback whales in the year 2018

5 0
4 years ago
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