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3 years ago

A traffic helicopter descends 142 meters to be 430 meters above the ground, as illustrated in the diagram to the

Mathematics

1 answer:

Likurg_2 [28]3 years ago

8 0

430m+142m=h

The original height of the helicopter would be 142m higher than what it just descendet to.

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Help please look below

Gwar [14]

A is located, as you look A is past -2 almost hitting -3 making the mark 2.8 so the answer is A

3 0

2 years ago

The following information is obtained from two independent samples selected from two normally distributed populations.

AysviL [449]

A. The point estimate of μ1 − μ2 is calculated using the value of x1 - x2, therefore:

μ1 − μ2 = x1 – x2 = 7.82 – 5.99

μ1 − μ2 = 1.83

B. The formula for confidence interval is given as:

Confidence interval = (x1 –x2) ± z σ

where z is a value taken from the standard distribution tables at 99% confidence interval, z = 2.58

and σ is calculated using the formula:

σ = sqrt [(σ1^2 / n1) + (σ2^2 / n2)]

σ = sqrt [(2.35^2 / 18) + (3.17^2 / 15)]

σ = 0.988297

Going back to the confidence interval:

Confidence interval = 1.83 ± (2.58) (0.988297)

Confidence interval = 1.83 ± 2.55

Confidence interval = -0.72, 4.38

3 0

3 years ago

What is the missing term in the quadratic expression below (2x-3)(x+4)=2x^2+ ___ - 12

Allushta [10]

5x is the missing term

8 0

3 years ago

Multiply. write in simplest form. 2/5 x 15/16

shtirl [24]

$\frac{3}{8}$

8 0

2 years ago

A certain star is 2.4 x 102 light years from the Earth. One light year is about 5.9 x 1012 miles. How far

Studentka2010 [4]

Answer:

2.5 x $10^{15}$ miles

Step-by-step explanation:

We are given that 1 light year ≈ 5.9 x $10^{12}$ miles so:

4.3 x 10² light year · <u>5.9 x </u> $10^{12}$ <u> miles </u>
1 light year

Multiply 4.3 an 5.9 and round to 2 significant digits then add the exponents:

≈25 x $10^{14}$

This is not the scientific notation since the number is not between 0 and 10 so we move the decimal point by 1 place to the left. We then add 1 to the exponent to obtain the final answer:

≈ 2.5 x $10^{15}$ miles

6 0

2 years ago