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3 years ago

What number belongs in the space next to 10? Look at pic. A)19 B)18 C)17 D)16 E)15

Mathematics

1 answer:

AleksandrR [38]3 years ago

5 0

the equation is 2x-1 right so all you have to do is plug and go

2x-1

2x10-1

20-1

so your answer would be A)19

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Integrated mathematics 2. need help with chapter 5 test please

Pani-rosa [81]

Answer:

1/4

Step-by-step explanation:

$\text{Diamonds, spades, clubs and hearts make up the 4 suits of a deck of cards, }$

$\text{which contains 52 cards. There are 13 diamonds in a pack.}$

$\text{Probability of an event:}$

$\text{ Number of favorable outcomes / Total number of outcomes}$

$\text{Probability of getting a diamon}d = \frac{13}{52} = \frac{1}{4}.$

$\text{So the chance that you draw out a diamond from a deck}=\frac{1}{4}$ .

8 0

2 years ago

Please help ASAP

sashaice [31]

I don’t know I’m only in 7th grade but 56

3 0

3 years ago

, Hayley sold 20 tickets to the school play for a total of $225 early bird tickets were $10 and regular price tickets were $15 w

Lady_Fox [76]

Answer:

15 early tickets were sold and 5 regular tickets were sold.

Step-by-step explanation:

Let x be the number of early bird tickets sold and y be the number of regular tickets sold.

Total number of tickets sold = 20

Thus, we can write the equation,

$x + y = 20$

Cost of early bird ticket = $10

Cost of regular tickets = $15

Total cost = $225

Thus, we can write the equation,

$225 = 10x + 15y$

We solve the equation by elimination method by multiplying first equation by 10 and subtracting.

$10x + 15y-(10x+10y) = 225 - 200\\5y = 25\\\Rightarrow y=5\\x + 5 = 20\\\Rightarrow x = 15$

Thus, 15 early tickets were sold and 5 regular tickets were sold.

5 0

3 years ago

What is the value of x to the nearest tenth? 29.6 X 73° 33°

Makovka662 [10]

29.6+73+33=135.6 180-135.6=44.4

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3 years ago

A company did a quality check on all the packs of trail mix it manufactured. Each pack of trail mix is targeted to weigh 9.25 oz

kifflom [539]

I'm not quite sure, but the signs *might* have to be greater/less than or equal to, not just greater/less than. Anyways, it can't be an "or" situation because each pack needs to fit ALL criteria. This needs to be an "and" problem.

4 0

3 years ago

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