Question

 FIRST ANSWER GETS BRAINLIEST!!!!      At 5:45 p.m., a jet is located 108 mi due east of a city. A second jet is located 214 mi due north of the city.
 
To the nearest tenth of a mile, what is the distance between the two jets?

Answer 1

239.7 mile is the answer.

Answer 2

It is like a triangle
North which is the leg of it
And east is the same
Plug it into Pythagoras's theorem
108^2+214^2=x^2
Which equals 239.7 mile