Which of the following is the equivalent resistance of the circuit shown?

What provocative statement is Oscar Wilde making?

ASHA 777 [7]

None. He passed away in Paris in 1900 .

8 0

3 years ago

You wish to make a simple amusement park ride in which a steel-wheeled roller-coaster car travels down one long slope, where rol

Crazy boy [7]

Answer:

(a) The car is going approximately 40.43 m/s at the bottom of the hill

(b) The thermal energy will increase by 607,268.76 J

Explanation:

In the question, we have;

The height of the roller coaster above ground = 83.4 m

The mass of the roller coaster, m = 743.0 kg

(a) By the conservation of energy principle, we have;

The potential energy at the top of the hill, P.E., is equal to the kinetic energy at the bottom of the hill, K.E.

∴ P.E. = K.E.

P.E. = m·g·h

Where;

m = The mass of the roller coaster = 743.0 kg

g = The acceleration due to gravity = 9.8 m/s²

h = The height of the roller coaster = 83.4 m

Therefore, we have;

P.E. = 743.0 kg × 9.8 m/s² × 83.4 m = 607,268.76 J

P.E. = 607,268.76 J

K.E. = 1/2·m·v²

∴ K.E. = 1/2 × 743.0 kg × v²

P.E. = K.E.

∴ P.E. = K.E. = 607,268.76 J

1/2 × 743.0 kg × v² = 607,268.76 J

v² = 607,268.76 J/(1/2 × 743.0 kg) = 1,634.64 m²/s²

v = √(1,634.64 m²/s²) ≈ 40.43 m/s

(b) Given that the material wheel moves along polystyrene track, the sound released will be minimal and almost all the kinetic energy will be converted to heat energy when the train stops, therefore, the thermal energy will increase by K.E. = 607,268.76 J

7 0

3 years ago

Which pair of atoms will form a covalent molecule?

lyudmila [28]

Covalent molecules are molecules that have a sharing of electrons occurring between them, and this most commonly occurs between two non- metals. Therefore, 1 atom of oxygen and 2 atoms of hydrogen will form a covalent bond and this molecule is known as water

7 0

3 years ago

UV radiaGon having a wavelength of 120 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum kine

Solnce55 [7]

Answer:

K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J

Explanation:

First we calculate the energy of photon:

E = hc/λ

where,

E = Energy of Photon = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength = 120 nm = 1.2 x 10⁻⁷ m

Therefore,

E = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(1.2 x 10⁻⁷ m)

E = (16.565 x 10⁻¹⁹ J)(1 eV/1.6 x 10⁻¹⁹ J)

E = 10.35 eV

Now, from Einstein's Photoelectric equation we know that:

Energy of Photon = Work Function + K.E of Electron

10.35 eV = 4.82 eV + K.E

K.E = 10.35 eV - 4.82 eV

4 0

3 years ago

A Go Kart (m = 35 kg) has a top speed of 12 m/s . A student traveling at top speed locks the brake to avoid hitting a bus after

Sergeu [11.5K]

Answer:

350 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of Go Kart = 35 kg

Initial velocity (u) = 12 m/s

Distance (s) = 7.2 m

Force (F) =?

Next, we shall determine the acceleration of the Go Kart. This can be obtained as follow:

Initial velocity (u) = 12 m/s

Distance (s) = 7.2 m

Final velocity (v) = 0 m/s

Acceleration (a) =.?

v² = u² + 2as

0² = 12² + (2 × a × 7.2)

0 = 144 + 14.4a

Collect like terms

0 – 144 = 14.4a

– 144 = 14.4a

Divide both side by 14.4

a = – 144 / 14.4

a = – 10 m/s²

The negative sign indicate that the Go Kart is decelerating when the brake was applied.

Finally, we shall determine the force the Go Kart have when the student locked the brake. This can be obtained as follow:

Mass (m) of Go Kart = 35 kg

Acceleration (a) = 10 m/s

Force (F) =?

F = ma

F = 35 × 10

F = 350 N

Thus, the Go Kart has a force of 350 N when the student locked the brake.

7 0

3 years ago