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Marizza181 [45]
3 years ago
6

In a drill during basketball practice, Sally runs the length of the 30- meter court and back. Sally does this in 60 seconds. Wha

t is her speed: A. 0 meters/seconds B. 0.5 meters/seconds C. 3 meters/seconds D. 30 meters/seconds
Please answer now. I have to answer this today. And explain if you can​
Physics
1 answer:
Juliette [100K]3 years ago
6 0

Hey!

-----------------------------------------------

Formula:

speed = distance ÷ time

-----------------------------------------------

Solution:

Distance is 60 meters.

Time is 60 seconds.

speed = 60 / 60

speed = 1 meters/seconds

-----------------------------------------------

Answer:

1 meters/seconds.

-----------------------------------------------

Hope This Helped! Good Luck!

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VikaD [51]

Answer:

stryo:  1

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brick: 2

aluminum: 2.7

Explanation:

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6 0
2 years ago
If your brakes give out, why can't you just pull the keys out of the ignition?
Pachacha [2.7K]

There should be a small amount of play in the wheel when the steering is locked. Gently pull the key from the ignition while you slowly jiggle the steering wheel back and forth. If this is the cause of the problem, the key should come out after a little effort.

5 0
2 years ago
Suppose that Hubble's constant were H0 = 51 km/s/Mly (which is not its actual value). What would the approximate age of the univ
bija089 [108]

Given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.

Given the data in the question;

Hubble's constant; H_0 = 51km/s/Mly

Age of the universe; t = \ ?

We know that, the reciprocal of the Hubble's constant ( H_0 ) gives an estimate of the age of the universe ( t ). It is expressed as:

Age\ of\ Universe; t = \frac{1}{H_0}

Now,

Hubble's constant; H_0 = 51km/s/Mly

We know that;

1\ light\ years = 9.46*10^{15}m

so

1\ Million\ light\ years = [9.46 * 10^{15}m] * 10^6 = 9.46 * 10^{21}m

Therefore;

H_0 = 51\frac{km}{\frac{s}{Mly} } = 51000\frac{m}{s\ *\ Mly}  \\\\H_0 = 51000\frac{m}{s\ *\ (9.46*10^{21}m)} \\\\H_0 =  5.39 *10^{-18}s^{-1}\\

Now, we input this Hubble's constant value into our equation;

Age\ of\ Universe; t = \frac{1}{H_0}\\\\t = \frac{1}{ 5.39 *10^{-18}s^{-1}} \\\\t = 1.855 * 10^{17}s\\\\We\ convert\ to\ years\\\\t =  \frac{ 1.855 * 10^{17}}{60*60*24*365}yrs \\\\t = \frac{ 1.855 * 10^{17}}{31536000}yrs\\\\t = 5.88 *10^9 years

Therefore, given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.

Learn more: brainly.com/question/14019680

6 0
2 years ago
--
enot [183]

Answer: 3 square feet

Explanation: I took the test

6 0
3 years ago
How many meters are there in 4.80 ly ?
Masja [62]
Since each light year is approximately 9 trillion kilometres, 4.80 light years is 43.2 trillion kilometres, or 43,200,000,000,000,000 metres
6 0
3 years ago
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