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3 years ago

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A swimming pool contains x (less than 0.02) grams of chlorine per cubic meter. the pool measures 5 meters by 50 meters and is 2

meters deep. some water will be drained and replaced by water contain 5 grams of chlorine per cubic meter. how much water should be drained so the pool ends up with 0.02 grams of chlorine per cubic meter.

1 answer:

zubka84 [21]3 years ago

3 0

The solution for this problem would be:(10 - 500x) / (5 - x)
so start by doing:
x(5*50*2) - xV + 5V = 0.02(5*50*2)
500x - xV + 5V = 10
V(5 - x) = 10 - 500x
V = (10 - 500x) / (5 - x)
(V stands for the volume, but leaves us with the expression for x)

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Since it is a polytropic Process

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