Answer:
k1 + k2
Explanation:
Spring 1 has spring constant k1
Spring 2 has spring constant k2
After being applied by the same force, it is clearly mentioned that spring are extended by the same amount i.e. extension of spring 1 is equal to extension of spring 2.
x1 = x2
Since the force exerted to each spring might be different, let's assume F1 for spring 1 and F2 for spring 2. Hence the equations of spring constant for both springs are
k1 = F1/x -> F1 =k1*x
k2 = F2/x -> F2 =k2*x
While F = F1 + F2
Substitute equation of F1 and F2 into the equation of sum of forces
F = F1 + F2
F = k1*x + k2*x
= x(k1 + k2)
Note that this is applicable because both spring have the same extension of x (I repeat, EXTENTION, not length of the spring)
Considering the general equation of spring forces (Hooke's Law) F = kx,
The effective spring constant for the system is k1 + k2
An object will remain at rest of maintain constant straight-line motion unless acted on by a force that is c. unbalanced
Answer:
I thinck it would be 48.0
Answer:
maximum kientcie energy is 4 Joules.
Explanation:
When an object moves in a circular path, the tension acting on the cord is equal to the centripetal force.
Here, the cord will break if its tension exceeds 16 N and the radius of the circular path is 0.5 m. So,
.......(1)
We know that the kinetic energy of the object is given by :
Putting equation (1) in above equation as :
So, the maximum kinetic energy the object can have is 4 Joules.
