Ask question

Ask question

All categories

2 years ago

13

20 years later, the same runner now wants a pierce of 5 miles in 55 minutes. How many minutes will it take him to run 1 mile at

this pace?

1 answer:

Elan Coil [88]2 years ago

8 0

Answer:

It will take 11 minutes per mile

Step-by-step explanation:

If he wants to run all the miles equally, just divide 55 by 5 to get an equal amount of minutes.

You might be interested in

A bottle of water is 2/3 full. You drink the given portion of

Citrus2011 [14]

Answer:

1/2

Step-by-step explanation:

Step 1: You would multiply 2/3 by 3/4.

(Hint: if it is ____ of ____, you would most likely multiply)

Step 2: 2×3/3×4

Step 3: 2×3=6

Step 4: 3×4=12

Step 5: 6/12

Step 6: Simplify 6/12 = 3/6 = 1/2

Hope this helps :)

3 0

2 years ago

Read 2 more answers

WILL PICK BRAINLIEST!!!

andreyandreev [35.5K]

we are given

$f(x)=10(2)^x$

now, we can compare it with

$f(x)=a(b)^x$

we can find b

we get

$b=2$

now, we are given

How would the graph change if the b value in the equation is decreased but remains greater than 1

Let's take

b=1.8

$f(x)=10(1.8)^x$

b=1.6

$f(x)=10(1.6)^x$

b=1.4

$f(x)=10(1.4)^x$

b=1.2

$f(x)=10(1.2)^x$

now, we can draw graph

now, we will verify each options

option-A:

we know that all y-value will begin at y=0

because horizontal asymptote is y=0

so, this is FALSE

option-B:

we can see that

curve is moving upward when b decreases for negative value of x

but it is increasing slowly for negative values of x

so, this is FALSE

option-C:

we can see that

curve is moving upward when b decreases for negative value of x

but it is increasing slowly for negative values of x

so, this is TRUE

option-D:

we know that curves are increasing

so, the value of y will keep increasing as x increases

so, this is TRUE

option-E:

we can see that

curve is moving upward when b decreases for negative value of x

but it is increasing slowly for negative values of x

so, this is FALSE

4 0

2 years ago

Read 2 more answers

State of the triangles in each pair of similar. If so, State how you know they are similar and complete the similarity statement

Vinil7 [7]

Answer:

b. not similar

Step-by-step explanation:

The given sides* have the ratio 30:39 = 10:13 in one triangle and the ratio 20:27 = 10:13.5 in the other triangle. Since these ratios are different, the triangles cannot be similar.

____

* These are the sides bracketing the vertical angles at T. If the triangles were similar, the three sides would have to have the ratios 10 : 13 : 13.5.

However, the geometry shown would require that the angle opposite side 13.5 in one triangle have the same measure as the angle opposite side 13 in the other triangle. That is not possible, so it is not possible for these triangles to be similar.

6 0

2 years ago

When five times a number is decreased by 4, the result is 26.<br> What is the number?

ikadub [295]

Answer:

5 x 6 = 30 - 4 = 26

so the answer is 6

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it

gavmur [86]

Answer:

a) $P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b) $P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c) A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

Purchased Gum Kept the Money Total

Students Given 4 Quarters 25 14 39

Students Given $1 Bill 15 29 44

Total 40 43 83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}$

And if we replace we got:

$P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}$

And if we replace we got:

$P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0

3 years ago