Y=a(x-h)^2+k
vertex form is basically completing the square
what you do is
for
y=ax^2+bx+c
1. isolate x terms
y=(ax^2+bx)+c
undistribute a
y=a(x^2+(b/a)x)+c
complete the square by take 1/2 of b/a and squaring it then adding negative and postive inside
y=a(x^2+(b/a)x+(b^2)/(4a^2)-(b^2)/(4a^2))+c
complete square
too messy \
anyway
y=2x^2+24x+85
isolate
y=(2x^2+24x)+85
undistribute
y=2(x^2+12x)+85
1/2 of 12 is 6, 6^2=36
add neagtive and postivie isnde
y=2(x^2+12x+36-36)+85
complete perfect square
y=2((x+6)^2-36)+85
distribute
y=2(x+6)^2-72+85
y=2(x+6)^2+13
vertex form is
y=2(x+6)^2+13
Answer:
Step-by-step explanation:
radius=diameter/2
13/2
6.5
circumference of a circle=2πr
=2*3.14*6.5
=40.82 feet
=
Answer:
The domain is all real numbers except x=3
Step-by-step explanation:
Assuming you mean
f(x) = 1/(x-3)
The domain is all numbers that x can take
This function is define except when the denominator goes to zero
x-3 cannot be zero
x cannot be 3
The domain is all real numbers except x=3
The answer should be 1/3
Cause u take 2/5=base*6/5
Divide 6/5 from both sides
The answer should be 1/3
I'm pretty sure that they are there to show symmetry
