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3 years ago

2

Physics

1 answer:

Paha777 [63]3 years ago

8 0

Answer:

Explanation:

because you ate multplying 10×8=80

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An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie

leva [86]

To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

$MV=mv$

Where

M=Heavier mass

V = Velocity of heavier mass

m = lighter mass

v = velocity of lighter mass

That equation in function of the velocity of heavier mass is

$V = \frac{mv}{M}$

Also we have that $m/M = 1/7 times$

On the other hand we have from law of conservation of energy that

$W_f = KE$

Where,

W_f = Work made by friction

KE = Kinetic Force

Applying this equation in heavier object.

$F_f*S = \frac{1}{2}MV^2$

$\mu M*g*S = \frac{1}{2}MV^2$

$\mu g*S = \frac{1}{2}( \frac{mv}{M})^2$

$\mu = \frac{1}{2} (\frac{1}{7}v)^2$

$\mu = \frac{1}{98}v^2$

$\mu = \frac{1}{g(98)(5.1)}v^2$

Here we can apply the law of conservation of energy for light mass, then

$\mu mgs = \frac{1}{2} mv^2$

Replacing the value of $\mu$

$\frac{1}{g(98)(5.1)}v^2 mgs = \frac{1}{2}mv^2$

Deleting constants,

$s= \frac{(98*5.1)}{2}$

$s = 249.9m$

7 0

4 years ago

1. A 56.2 kg ball is loaded into a 1.27kg cannon. The cannon is at rest when it is ignited. Immediately after the impulse of the

aleksandrvk [35]

Answer:

vc = v cannon

mc = m cannon

vb = v ball

mb = m ball

vc = d / t

= (6.1 cm) / (0.0218 s)

= 280 cm/s

mb x vb = -mc x vc

(negative as it is in the opposite direction)

(0.0562) x vb = - (1.27) x (-280)

vb = - (1.27) x (-280) / (0.0562)

= 6323.26 cm/s

ball = 63.2 m/s

cannon = 2.8 cm/s - recommend changing to m before calculations

7 0

3 years ago

Suspend a heavy weight by two pieces of rope. Tension is greatest when the ropes

bija089 [108]

Assuming that the angle is the same for both ropes, then D. is the answer. You have to consider also if the ropes are close together or far apart and if the force to move the object is in line with the ropes or perpendicular to them.
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3 0

4 years ago

B) The student continues her investigation by loading the spring with different masses. The table shows her result.

liubo4ka [24]

Answer:

1) Id say the dependant is the distance

2) the force is calculated by dividing the mass by 100

Explanation:

the dependant variable is the variable you measure wich is in this case distance.

3 0

3 years ago

now suppose that we have attached not just two springs in series, but N springs. Write an equation that expresses the effective

sammy [17]

Answer:

$k_{eq} = \frac{k}{N}$

Explanation:

For this exercise let's use hooke's law

F = - k x

where x is the displacement from the equilibrium position.

x = $- \frac{F}{k}$

if we have several springs in series, the total displacement is the sum of the displacement for each spring, F the external force applied to the springs

x_ {total} = ∑ x_i

we substitute

x_ {total} = ∑ -F / ki

F / k_ {eq} = -F $\sum \frac{1}{k_i}$