Write an equation to show all elements:
Cost of 4 lots of b (beads) + cost of 4p (pendants) = $18.80
Put values in;
9.29 + 4p = 18.80
4p = 18.80 - 9.20
4p = 9.60
p = 2.40 cost of each pendant
A) 5 to be chosen among a Total : 10 Men + 8 Women
¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five
b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56
So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees
c) 3 Women and 2 Men:
⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M
d) More women than men, it means:
3 W + 2 M OR (we have found it in c) = 2,520)
4 W + 1 M OR ⁸C₄ x ¹⁰C₁ →→→→ = 700
5 W + 0 M OR ⁸C₅ x ¹⁰C₀ →→→→ = 56
Total where W>M = 3,276 groups of 5 where women are at least 3
21/6 simplified 7/2 or 3 1/2
Answer:
13, 587 times
Step-by-step explanation:
Population of City A
= 1.9 * 105 = 157.5
Population of City B
= 1,070,000
Population of City C
= 2 * city B
= 2 * 1,070,000
= 2,140,000
The population of City C is how many times the population of City A?
City C = x * City A
2,140,000 = x * 157.5
x = 2,140,000 / 157.5
x = 13587.30
The population of City C is 13587.30 times the population of City A.
Hope this helps :)
It should be 10, The scale goes off of what the numbers count by so like 10,20,30,40,50,60 if I’m not mistaken
