Answer:
After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.
Step-by-step explanation:
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The independent variable is the factor that you purposely change or control in order to see what effect it has. The variable that responds to the change in the independent variable is called the dependent variable. It depends on the independent variable. The independent variable is graphed on the x-axis.
To identify dependent studies variables, search for objects in your studies query or speculation that sees the result, effect, or outcome of changing the independent variable. The basic rule is to search for what reasons for reactions and what receives the results.
The statistical courting between variables is referred to as their correlation. A correlation might be high-quality, which means each variable circulates in the same direction, or bad, meaning that once one variable's price will increase, the opposite variables' values decrease.
Making sure that certain research variables are managed will increase the reliability and validity of the test, by ensuring that other causal consequences are removed. This safeguard makes it simpler for other researchers to repeat the experiment and comprehensively test the results.
Learn more about variables here brainly.com/question/2804470
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Answer:
Okay so, first put a dot on the number three. Next, go down one and over two from that spot (2, 2) and so on.
Step-by-step explanation:
Answer:
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Answer:
Its volume is 2 times the original volume.
Step-by-step explanation:
It cant be the first 2 because you are making it bigger, not smaller. and it cant be the last one because you are only doubling one of the parts.