Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
Answer:
2nd option = 3 is the answer.
Answer:
10.626
Step-by-step explanation:
There's multiple ways to go about it. See how
5.06 * 2.1 = (5 + 0.06)(2 + 0.1) = 5*2 + 0.06*2 + 5*0.1 + 0.06*0.1 =
= 10 + 0.12 + 0.5 + 0.006 = 10.626
Please notice how breaking up the product into smaller parts has let us make all the computations without too much hassle.
Answer:
20 games
Step-by-step explanation:
Let
x ----> total games played this season
we know that
12 games represent 60% of the games they have played this season
so
using proportion
Find out how many games represent a percentage of 100%
