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3 years ago

IM MARKING BRAINLIEST

Mathematics

2 answers:

nlexa [21]3 years ago

8 0

5/6 yards

Step-by-step explanation:

$\frac{1}{6} + \frac{4}{6} = \frac{5}{6}$

kompoz [17]3 years ago

7 0

Answer:

5/6 yards of fabric

Step-by-step explanation:

4/6 yards + 1/6 yards = 5/6 yards

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-12 = 8 - 4x. what does x equal

Usimov [2.4K]

-12= 8-4x
-8 -8
-20=-4x
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5=x

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4 years ago

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NEED ANSWER FAST PLEASE HELP!!!

viktelen [127]

Answer:

Step-by-step explanation:

plug in the coordinates for x and y

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3 years ago

Sam and Ella were running in a race. Sam ran ⅞ of a mile and Ella ran 5/10 of a mile. At the end of the race they wanted to comp

earnstyle [38]

Answer:

ELLA

Step-by-step explanation:

Given that :

Distance covered by Ella = 5/10

Distance covered by Sam = 7/8

Comparing each distance to 1/2

Ella = 5/ 10 = 1/2 ; 1/2 = 1/2 = 0.5

Sam = 7/8 = 0.875 ; comparing with 1/2

0.875 > 0.5

Given

Sam ran farther Than ELLA

Because 0.875 > 1/2

0.875 - 0. 5 = 0.375

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3 years ago

Write two different pairs of decimals whose sums are 14.1 and one pair should involve regrouping

Oksi-84 [34.3K]

The answer is 8.4 and 5.7

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3 years ago

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Plz solve this problem of trigonometry<br>i am an aakashian

makkiz [27]

Step-by-step explanation:

$\bf L.H.S = \tt \dfrac{sec\: \theta + tan \: \theta - 1}{tan \: \theta - sec \: \theta + 1} \\ \\$

$: \implies \tt \dfrac{\frac{1}{cos \: \theta} + \frac{sin \: \theta}{cos \: \theta} - 1}{ \frac{sin \: \theta}{cos \: \theta} - \frac{1}{cos \: \theta} + 1 } \: = \dfrac{1 + sin \: \theta - cos \: \theta}{sin \: \theta + cos \: \theta} \\ \\$

$: \implies \tt\dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta + (cos \: \theta - 1)} \: \times \: \dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta - (cos \: \theta - 1)} \\ \\$

$: \implies \tt\dfrac{ sin^{2} \: \theta + cos^{2} \: \theta + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: (cos \: \theta - 1)}{sin^{2} \: \theta - (cos \: \theta - 1)^{2} } \\ \\$

$: \implies \tt\dfrac{1 + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - 1 + 2 \: cos \: \theta } \\ \\$

$: \implies \tt\dfrac{2 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - sin^{2} \: \theta - cos^{2} \: \theta + 2 \: cos \: \theta } \\ \\$

$: \implies \tt\dfrac{2 (1 - \: cos \: \theta )- 2 \: sin \: \theta (1 - \: cos \: \theta)}{ 2 \: cos \: \theta - 2 \: cos^{2} \: \theta} \\ \\$

$: \implies \tt\dfrac{(2 + 2 \: sin \: \theta) \: \cancel{(1 - cos\: \theta)}}{2 \: cos \: \theta \: \cancel{(1 - cos \: \theta)}} \: = \: \dfrac{1 + sin \: \theta}{cos \: \theta} \\ \\$

$: \implies\tt\dfrac{1 + sin \: \theta}{cos \: \theta} \: \times \: \dfrac{1 - sin \: \theta}{1 - sin \: \theta} \\ \\$

$: \implies\tt\dfrac{1 + sin^{2} \: \theta}{cos \: (1 - sin \: \theta)} \\ \\$

$: \implies\tt\dfrac{cos^{2} \: \theta}{cos \: \theta (1 - sin \: \theta)} \\ \\$

$: \implies\tt\dfrac{cos \: \theta}{1 - sin \: \theta} \: = \: \bf{ R.H.S}\\ \\$

$\huge\bigstar \:\underline{\red{\sf Hence, Proved}} \: \bigstar \\$

6 0

4 years ago