Question

Complete the square to find the vertex of this parabola

Answer 1

Answer:

$(2,-6)$

Step-by-step explanation:

$x^2-4x+y+10=0$

$y=x^2+4x-10$

$y=-(x^2-4x)-10$

$=-(x^2-4x+4)-10+4$

$=-(x-2)^2-6$

$y=-(x-2)^2+(-6)$

$h=2 ~and~ k=-6$

So, vertex → (2,-6)

$------------$

hope it helps..

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