Answer:
segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13
Step-by-step explanation:
Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).
1. Reflection over x = 1 maps vertices A, B and C as follows
- A(-3,3)→A'(5,3);
- B(1,-3)→B'(1,3);
- C(-3,-3)→C'(5,-3).
2. Dilation by a scale factor of 2 from the origin has the rule
(x,y)→(2x,2y)
So,
- A'(5,3)→A''(10,6);
- B'(1,3)→B''(2,6);
- C'(5,-3)→C''(10,-6)
See attached diagram for details
Note that
so
Begin solving like you normally would. Add 2.25 to both sides and subtract 9x from both sides to try getting all x values on one side. However, you will find that after subtracting 9x from both sides, all x values go away, and you end with -2.25=1.6. This is not true (-2.25 is not 1.6), so the answer is no solution. There is no value of x which satisfies that equation.
Answer:
y = 3x + 3
Step-by-step explanation:
First, you check for the y-intercept, which is 3 for this equation.
In order to find the slope, pick two points and apply the slope formula.
I would just use rise/run. The slope should be 3/1.
Answer:
x=90-22
x=68
as the ray divide the right angle into 2
Step-by-step explanation:
9x² + 6 = 12x
3x² + 2 = 4x
3x² − 4x + 2 = 0
Use quadratic formula.
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ -(-4) ± √((-4)² − 4(3)(2)) ] / 2(3)
x = [ 4 ± √(16 − 24) ] / 6
x = [ 4 ± √(-8) ] / 6
x = (4 ± 2i√2) / 6
x = (2 ± i√2) / 3
