Answer:
Step-by-step explanation:
is there anyway you can take a closer picture it is not letting me see well
9514 1404 393
Answer:
15
Step-by-step explanation:
In vector form, the equation of point p on the line can be written as ...
p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t
p = (-3, -4) +t(28, 42)
p = (-3, -4) +14t(2, 3)
where t takes on any value between 0 and 1.
If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.
There are 15 values that n can have in the allowed range.
The caterpillar touches 15 points with integer coordinates.
Answer:
You may or may not need to include the units.
A = 18x - 18
P = 6x + 6
Graph is attached below. (2, 18)
Step-by-step explanation:
Substitute the information we need, "l" and "w", into the formulas.
l is for length, 6cm.
w is for width, (3x - 3)cm.
Use the formula for area of a rectangle.
A = lw
A = (6)(3x-3)cm²
A = (18x - 18)cm² or 18x - 18
Use the formula for perimeter of a rectangle.
P = 2(l + w)
P = 2(6 + (3x - 3))cm
P = 2(3x + 3)cm
P = (6x + 6)cm or 6x + 6
Linear equations are written in the form y = mx + b, so we do not need to factor or further simplify the formulas.
To graph, first turn the "m" value into a fraction form.
8 -> 8/1
6 -> 6/1
You need two points to graph each line.
For each equation, the first point is on the y-axis at the "b" value. Then use the "m" in the equation to count the number of units up (numerator) and to the right (denominator).
The solution is (2,18)
Answer:
0
Step-by-step explanation:
∫ sin²(x) cos(x) dx
If u = sin(x), then du = cos(x) dx.
∫ u² du
⅓ u³ + C
⅓ sin³(x) + C
Evaluate between x=0 and x=π.
⅓ sin³(π) − ⅓ sin³(0)
0