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scZoUnD [109]
3 years ago
9

Ellie practices piano 2/3 h per day, several days each week. She practiced piano 32/23 hours during the summer.

Mathematics
1 answer:
butalik [34]3 years ago
3 0

Let us assume that the number of days she practiced the piano to be "d"

Since she practiced 2/3 hours a day, the total number of hours would be: 2/3*d

Now we are given the total number of hours during summer that she practiced  be be equal to 32/23

So we equate 2/3 * d to 32/23 to find d

2/3*d = 32/23

d = (32/23)/ (2/3)

d = (32/23) * (3/2)

d = 48/23 hours

The equation that can be used to find the number of days that she practiced piano during the summer is 2/3*d = 32/23

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Answer:

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Step-by-step explanation:

Given:

KL ║ NM ,

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m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

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