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STALIN [3.7K]
3 years ago
5

Ian wants to promote his band on the internet. Site a offers website hosting for $4.95 per month with a $49.99 startup fee. Site

b offers website hosting for $9.95 per month with no startup fee. Write and solve an inequality to determine how many months lan could have his wedsite on site b and still keep his total cost less than site a
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0
 <span>I believe for twelve (12) months. 

Site A: $49.95 plus $59.40(4.95 x 12) equals $109.35 

Site B: $9.95 x 12 equals $119.40 

No, wait that's not right. 

Okay, at 8 months, site A is pretty much at $90 (forget the nickels) and site B is $80 so site B is less. 
At 7 months, site A is $85 and site B is $70 so site B is less. 
At 9 months, site A is $95 and site B is $90 so site B is less. 
At 10 months, site A $100 and site B is $100 

It's got to be around 10 months somewhere. 

Ten months would be $99.45 for site A and $99.50 for site B so B is less. 

Eleven months is $104.40 for A and $109.45 for B so now B is more.</span>
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meriva

Answer:

sec~y=\frac{q}{r}

Step-by-step explanation:

tan ~y=\frac{7}{r} \\\\\frac{sin~y}{cos~y} =\frac{7}{r} \\\\sin~y=\frac{7}{r} cos~y\\sin ~y=\frac{7}{q} \\\frac{7}{q} =\frac{7}{r} cos~y\\sec~y=\frac{7}{r}  \times \frac{q}{7} =\frac{q}{r}

6 0
3 years ago
(5×10^5)+(6.182×10^6)<br> Pls answer in scientific notation
dimaraw [331]

Answer:

5.62*10^5

Step-by-step explanation:

5 --> 50; 10^5 --> 106

((50)*(10^6))+(6.182*10^6)

(56.182*10^6)

5.62*10^5

6 0
3 years ago
Find the slope of the line that passes through the pair of points
BlackZzzverrR [31]

Answer:

undefined

Step-by-step explanation:

To find the slope through 2 points

m = ( y2-y1)/(x2-x1)

   = ( -4 - -3)/(3 - 3)

    = ( -4+3)/(3-3)

    = -1/0

Since it is a number divided by zero, the slope is undefined

7 0
2 years ago
Solve it I need help
rusak2 [61]
It opens upward and the vertex is (2,-6) here are some plotted points: (0,6),(1,-3),(2,-6),(3,-3),(4,6). Hope that helps. I hate graphing but if you do it enough times you'll get the hang of it!
6 0
3 years ago
The management of a relatively new social networking website named BooglePlus is conducting a pilot study comparing use of its o
zavuch27 [327]

Answer:

0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

Step-by-step explanation:

Given the data in the question;

sample size n = 28

slope of the least squares regression line of y on x or sample estimate = 0.0623

standard error = 0.0224

95% confidence interval

level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05

degree of freedom df = n - 2 = 28 - 2 = 26

∴ the equation will be;

⇒ sample estimate ± ( t-test) ( standard error )

⇒ sample estimate ± ( t_{\alpha /2, df) ( standard error )

⇒ sample estimate ± ( t_{0.05 /2, 26) ( standard error )

⇒ sample estimate ± ( t_{0.025, 26) ( standard error )

{ from t table; ( t_{0.025, 26) = 2.055529 = 2.056

so we substitute

⇒ 0.0623 ± ( 2.056 )( 0.0224 )

Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

5 0
3 years ago
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