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Alex73 [517]
3 years ago
13

Lcm of 20, 3 quick math

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer:

least common multiple of 20 and 3? it would be 60.

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Solve for me please this is trigonometry
Vladimir79 [104]

Answer:

x= 23.4

Step-by-step explanation:

In a right triangle the tangent of an angle is the ratio of the opposite length over the adjacent*. In formulas, tan 54° = x/17 Solving for x, using a calculator for the tangent, x= 23.4

*I promise I didn't just spellcheck that.

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2 years ago
Mr Hughes is competing in the Mr. Legs campaign to raise money for the coral shores high school scholarship fund. On the first d
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<span>The number of dollars collected can be modelled by both a linear model and an exponential model. To calculate the number of dollars to be calculated on the 6th day based on a linear model, we recall that the formula for the equation of a line is given by (y - y1) / (x - x1) = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (3, 8) The equation of the line representing the model = (y - 2) / (x - 1) = (8 - 2) / (3 - 1) = 6 / 2 = 3 y - 2 = 3(x - 1) = 3x - 3 y = 3x - 3 + 2 = 3x - 1 Therefore, the amount of dollars to be collected on the 6th day based on the linear model is given by y = 3(6) - 1 = 18 - 1 = $17 To calculate the number of dollars to be calculated on the 6th day based on an exponential model, we recall that the formula for exponential growth is given by y = ar^(x-1), where y is the number of dollars collected and x represent each collection day and a is the amount collected on the first day = $2. 8 = 2r^(3 - 1) = 2r^2 r^2 = 8/2 = 4 r = sqrt(4) = 2 Therefore, the amount of dollars to be collected on the 6th day based on the exponential model is given by y = 2(2)^(5 - 1) = 2(2)^4 = 2(16) = $32</span>
4 0
3 years ago
Read 2 more answers
PLZ HELP 70 POINTS!!!!!
marin [14]

5^(x+7)=(1/625)^(2x-13)


We move all terms to the left:


5^(x+7)-((1/625)^(2x-13))=0



Domain of the equation: 625)^(2x-13))!=0


x∈R



We add all the numbers together, and all the variables


5^(x+7)-((+1/625)^(2x-13))=0


We multiply all the terms by the denominator



(5^(x+7))*625)^(2x+1-13))-((=0


We add all the numbers together, and all the variables


(5^(x+7))*625)^(2x-12))-((=0


We add all the numbers together, and all the variables


(5^(x+7))*625)^(2x=0

not sure if this is right :/


8 0
3 years ago
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Answer:

d

Step-by-step explanation:

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452, 453, 454, 456, etc.
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