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shutvik [7]
2 years ago
14

(2) The population density of a region in Alaska is 3,000 people/200 mi? Which of the

Mathematics
1 answer:
Vesna [10]2 years ago
8 0

Answer:

15 people/mi

Step-by-step explanation:

The population density of a region in Alaska is 3,000 people/200 mi.

We need to find the equivalent to the population density of this Alaskan region.

x=\dfrac{3000\ \text{people}}{200\ \text{mi}}\\\\x=\dfrac{30\ \text{people}}{2\ \text{mi}}\\\\x=\dfrac{15\ \text{people}}{\text{mi}}

So, the correct option is (c) "15 people/mi"

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It takes Karl 6 hours to drive 372 miles. If he drives at a constant speed during the 6 hours, what is his unit rate? At this ra
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3 years ago
Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

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2 years ago
What property can you use to write an equivalent expression for -5(x-2)? Explain.
emmainna [20.7K]

Answer:

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Step-by-step explanation:

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3 0
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Find the area under the standard normal curve to the left of
JulijaS [17]
A. z = 0.74
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c. z = 1.02
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d. z = -0.15
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