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evablogger [386]
3 years ago
14

The following information is known about a loan. Time = 8 years Interest rate = 14% Principal = $1,010 What is the total amount

of simple interest that is earned?
Mathematics
2 answers:
Mrac [35]3 years ago
7 0
Interest= principal*rate*time

dedylja [7]3 years ago
6 0

Answer:

$1131.20plz mark as brainliest

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, list the first five terms of each sequence, and identify them as arithmetic or geometric.
sveta [45]

Answer: -2, 2, 6, 10, 14

It is an Arithmetic sequence.

Step-by-step explanation:

Given Recursive formula : A(n + 1) = A(n) + 4 ,  for n ≥ 1 and A(1) = -2.

A(2)=A(1 + 1) = A(1) + 4=-2+4=2

A(3)=A(2 + 1) = A(2) + 4=2+4=6

A(4)=A(3 + 1) = A(3) + 4=6+4=10

A(5)=A(4 + 1) = A(4) + 4=10+4=14

Hence, the  five terms of given sequence= -2, 2, 6, 10, 14

Since, there is common difference of 4 in two consecutive terms.

Therefore, it is an Arithmetic sequence.

5 0
3 years ago
I NEED HELP ASAP!!!! SOLVE THIS IT'S AN IMAGE!!!!
joja [24]

Answer:

y = -7

Step-by-step explanation:

Put x = 2 in any one of the equation

5x +2y = -4

5*2 + 2y = -4

10 +2y = -4

      2y = -4 -10

      2y = -14

        y = -14/2

         y = -7

6 0
3 years ago
Read 2 more answers
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
2 years ago
Multiply the polynomials (5x^2+4x-4)(4x^3-2x+6)<br> Explain your steps!!
Lapatulllka [165]
So distribute using distributive property
a(b+c)=ab+ac so

split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24

the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24




4 0
2 years ago
I need help with this please help me i got it wrong
BartSMP [9]

It's a glitch I believe (screenshot and contact your teacher)

7 0
3 years ago
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