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Archy [21]
3 years ago
15

Express 26 as sum of 3 odd primes

Mathematics
1 answer:
vovangra [49]3 years ago
3 0
26 = 1, 3, 9, 13 i added 4 just incase u need sum extra
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1 3/10 x 18 please show work and answer
klasskru [66]

Answer:

Step-by-step explanation:

1 3/10 x 18

(1 x 10 +3)/10 = 13/10

13/10 x 18 = (13 x 18) / 10 = 234/10 = (234/2) / (10/2) = 117/5 = 23 2/5 (a fraction is a division)

7 0
3 years ago
Asap help!
prisoha [69]
We're given s = 8^(3/2) as the side length. If we square both sides then we have s^2 = [8^(3/2)]^2 = 8^3. Note how the '2's effectively cancel out. This is because we multiply the exponents (3/2) and 2 to get (3/2)*2 = (3/2)*(2/1) = (3*2)/(2*1) = 6/2 = 3.

So A = s^2 = 8^3 = 512 is the area of the square
4 0
4 years ago
Referring to the figure, find the volume of the solid shown. Round to the nearest whole number. Will mark brainliest...
nirvana33 [79]

Answer:

648

Step-by-step explanation:

FInd volume of bottom half (9x6x12)

find voume of pyramid 1/3Bh 1/3(11)(54)

4 0
3 years ago
Please help I'll give 45 points just ignore 1&2 and do 3 please
Readme [11.4K]

Answer:

$489.02

Step-by-step explanation:

3 0
3 years ago
what is the domain of f(x) = ³√x ? a). all real numbers b). positive numbers and zero c). all integers d). whole numbers
Mila [183]

Answer:

A


Step-by-step explanation:

<u>Domain is the </u><u>ALLOWED</u><u> x values in a function.</u>

  • Does plugging in any positive number pose a problem with getting an answer?

No.

  • Does plugging in 0 pose any problem?

No.

  • Does plugging in negative numbers pose any problem?

No. <em>Square root of negative numbers are not possible</em> BUT <em>cube root of negative numbers ARE possible</em>.

<em>Also, from the attached snapshot of the graph of f(x)=\sqrt[3]{x} , we can see that ALL real numbers are allowed for x</em>

7 0
3 years ago
Read 2 more answers
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