Answer:
So we have a triangle and a semicircle.
If the triangle is equilateral, this is:
AB = BC = 6cm
Then the area of the triangle is equal to (base*height)/2
in this case:
A = (6*6)/2 = 36/2 = 18cm^2.
And the diameter of the semicircle is equal to 6cm, then the diameter is 3cm
And if the area of a circle is A = pi*r^2
then the area of half a circle is:
A = (pi/2*)3^2 = pi*4.5cm^2
Then, the area of the triangle plus the area of the semicircle is:
Total area = 18cm^2 + pi*4.5^2
Answer:
<h2>3500</h2>
Step-by-step explanation:
Given the ratio of the profit, cost of materials and labour in the production of
an article to be 5:7:13 respectively, total ratio = 5+7+13 = 25
If the cost of labour is x, the cost of material will be 840+x (since the cost of materials is Le 840 more than that of labour) .
Let the total cost of producing the article be y.
Cost of labour = 13/25 * y = x
Cost of labour = 13y/25 = x.................... 1
Cost of material = 7/25*y = 840+x
Cost of material = 7y/25 = 840+x ..................... 2
From 1, 13y = 25x
x = 13y/25 ................... 3
Substituting equation 3 into 2:
7y/25 = 840+x
7y/25 = 840+13y/25
collect the like terms:
7y/25 - 13y/25 = 840
-6y/25 = 840
-6y = 25*840
y = 25*840/6
y = 3,500
<em>Hence the total cost of producing the article is 3500</em>
Answer:
12=d
Step-by-step explanation:
correct answer :)
Slope: 3, y-intercept: 4, equation: y = 3x + 4
Since we have two possible pieces of information and 2 items to solve for, we know this is a system of equations.
Our first piece of information is that our shorter leg (s) is 2 feet shorter than our longer leg (l). This can be written as s=l-2.
Our second piece of information is that using the Pythagorean theorem that our shorter leg squared plus our longer leg squared is equal to our hypotenuse squared. This can be represented by s^2+l^2=10^2. Now we can solve.
We have already isolated for s in our first equation, so we can substitute l-2 in.
(l-2)^2+l^2=10^2
l-2+l=10
2l-2=10
2l=12
l=6
Now we can substitute in for s in our simpler equation
s=6-2
s=4
We now know that using our knowledge of systems of equations, the side lengths of this right angle triangle are 6 and 4.
