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Alik [6]
3 years ago
5

Triangle ABC is an isosceles right triangle inscribed in a circle. The center of the circle is point D and the diameter of the c

ircle is AC.
Which of the following would not be true for the triangle and circle described above?

See Attached for choices

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

* AD is congruent to DC and BD <em>true</em>

* m∠B = 90° <em>true</em>

<u>* The measure of arc AC is equal to the measure of arc AB </u><u><em>not be true</em></u><em> ( The right answer  )</em>

* The measure of arc AB is equal to measure of arc BC <em>true</em>

Step-by-step explanation:

∵ D is the center of the circle and A , B and C are points on the circle

∴ AD , DB and DC are radii on the circle D

∴ AD ≡ DC ≡ DB

∵ AC passing through point D which is the center of the circle

∴ AC is the diameter of the circle D

∵ ∠B is opposite to the diameter of the circle and vertex B lies on the circle

∵ ∠B is an inscribed angle and  ∠ADC  is a central angle subtended by the same arc AC

∴m∠B = half m∠ADC

∵ m∠ADC = 180°

∴ m∠B = 90°

∵ The measure of arc AC = 180°

∵ ΔABC is isosceles and m∠B = 90°

∴ m∠BAC = m∠BCA = (180° - 90°) ÷ 2 = 45°

∵ ∠ACB is an inscribed angle subtended by arc AB

∴ m∠ACB = half measure of arc AB

∵ The measure of arc AB = 45° × 2 = 90°

∴ The measure of arc AC ≠ the measure of arc AB

∵ Δ ABC is an isosceles triangle and m∠B = 90°

∴ AB = BC

∵ AB subtended by arc AB

∵ BC subtended by arc BC

∴ The length of arc AB = the length of arc BC

∵ If two arcs are equal in length, then they will be equal in measure

∴ The measure of arc AB is equal to the measure of arc BC

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45) The function corresponds to graph A

46) The function corresponds to graph C

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Step-by-step explanation:

We know that the function f(x) is:

f(x)=(x-2)^{2}+1

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The function g(x) is given by:

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using f(x) we can find f(x-1)

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Puting it on g(x) we will get y value.

y=g(3)=(3-3)^{2}+1

y=g(3)=1

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

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g(x)=((x+2)-2)^{2}+1

g(x)=(x)^{2}+1

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2x

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Evaluatinf g(x) at this value of x we have:

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<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

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g(x)=(x-2)^{2}+1+2

g(x)=(x-2)^{2}+3

Let's find the first derivative and equal to zero to find x and y minimum value.

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Evaluatinf g(x) at this value of x we have:

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g(2)=3

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

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Let's find the first derivative and equal to zero to find x and y minimum value.

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Evaluatinf g(x) at this value of x we have:

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<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

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Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

1a) Well, if you add the y to both sides, you would get y=2x+4

1b) Since the main form is y=mx+b with m being the slope, the slope in y=2x+4 must be 2

1c) 6, because if x is 1, 2(1)+4=6

1d) I'm afraid you'll have to do that, just substitute in different numbers for x

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

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