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sammy [17]
4 years ago
7

If h left-parenthesis x right-parenthesis equals f left-parenthesis x right-parenthesis times g left-parenthesis x right-parenth

esis equals negative x superscript 2 baseline minus 3 ⁢ x plus 4, what are possible equations for f left-parenthesis x right-parenthesis and g left-parenthesis x right-parenthesis
Mathematics
1 answer:
alexgriva [62]4 years ago
4 0
Given
  h(x) = f(x)·g(x) = -x² -3x +4
Find
  Possible equations for f(x) and g(x)

Solution
  h(x) factors as -(x -4)(x +1)
There are an infinite number of possibilities for f(x) and g(x). Some of the simpler ones are ...
  f(x) = 4 -x; g(x) = x +1
or
  f(x) = -x -1; g(x) = x -4
or either of this with f and g swapped.

For some q(x), you can also have ...
  f(x) = (4 -x)×q(x); g(x) = (x +1)/q(x)
again, possibly with f and g swapped
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Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

3 0
3 years ago
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irakobra [83]

Answer:

B

Step-by-step explanation:

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cos30° = \frac{\sqrt{3} }{2} , then

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2x = 20\sqrt{3} ( divide both sides by 2 )

x = 10\sqrt{3} → B

7 0
3 years ago
Let f(x) = -x - 1 and g(x)=x2 + 4.<br> Find (fog)(0)
nexus9112 [7]

Answer:

-5

Step-by-step explanation:

We are asked to find f(g(0)).

Start with the inside which is g(0).

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So now we have f(g(0))=f(4).

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Since f(g(0))=f(4), then f(g(0))=-5.

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Answer:

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Step-by-step explanation:

According to the question

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